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maksim [4K]
4 years ago
6

if a lawyer bills $350/hour, how much does he makes every second? how much does he make per year? assume he works 50 hours per w

eek, 48 weeks per year.
Mathematics
1 answer:
serg [7]4 years ago
5 0

5.83  every second, and 840000 a year.

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Solve using the tangent formula(real answers only please)
Lilit [14]

9514 1404 393

Answer:

  21.07

Step-by-step explanation:

The tangent ratio is ...

  Tan = Opposite/Adjacent

For the given values, this is ...

  tan(36°) = x/29

Solving for x, we have ...

  x = 29·tan(36°)

  x ≈ 21.07

4 0
3 years ago
The lifetime of a leaf blower is exponentially distributed with a mean of 5 years. If you buy a 12 year old leaf blower, what is
snow_tiger [21]

Answer:

1.967 × 10⁻¹¹

Step-by-step explanation:

This is a conditional probability problem

Probability that a 12 year old leaf blower works for 5 more years = Probabilty that a leaf blower works for 17 years, given that it has worked for 12 years = P(17|12)

P(17|12) = P(17 n 12)/P(12)

P(17 n 12) = P(17)

Exponential random variable is given as

f(x) = λ e^(-λ.x)

λ = rate parameter = 5 years per blower

x = variable whose probability is required = 17

f(17) = 17 e^(-5×17)

f(17) = 17 e⁻⁸⁵ = 2.067 × 10⁻³⁶

f(12) = 12 e^(-5×12)

f(12) = 12 e⁻⁶⁰ = 1.051 × 10⁻²⁵

P(17|12) = (2.067 × 10⁻³⁶)/(1.051 × 10⁻²⁵)

P(17|12) = 1.967 × 10⁻¹¹

8 0
3 years ago
64% of 75 tiles show work
icang [17]
48 because, 
<span>For example
To find x percent of y you can just do </span>
<span>y times x/100 </span>
<span>So in this case </span>
<span>100 times 20/100 </span>
<span>which comes to 20 </span>
<span>so 20% of 100 is 20. </span>
5 0
3 years ago
1. D=5.9 ft.
Shtirlitz [24]

\qquad\qquad\huge\underline{{\sf Answer}}♨

Here's the solution ~

As we know, we can calculate the circumference of a circle in terms of its diameter as :

\qquad \sf  \dashrightarrow \:c =  \pi d

where, c = circumference and d = diameter

And also, circumference of circle is terms of radius (r) is :

\qquad \sf  \dashrightarrow \:c =  2\pi r

Now, let's move on to questions ~

<h3>First </h3>

\qquad \sf  \dashrightarrow \:3.14 \times 5.9

\qquad \sf  \dashrightarrow \: \approx18.53 \: ft

<h3 />

・ .━━━━━━━†━━━━━━━━━.・

<h3>Second</h3><h3 /><h3 /><h3 /><h3>\qquad \sf  \dashrightarrow \:3.14 \times 3.2</h3>

\qquad \sf  \dashrightarrow \: \approx10.048 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Third</h3>

\qquad \sf  \dashrightarrow \:3.14 \times 6.1

\qquad \sf  \dashrightarrow \: \approx19.15 \: ft

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fourth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  3.7

\qquad \sf  \dashrightarrow \: \approx2×11.62  \: m

\qquad \sf  \dashrightarrow \: \approx23.24  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Fifth </h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  6.2

\qquad \sf  \dashrightarrow \: \approx2× 19.47 \: units

\qquad \sf  \dashrightarrow \: \approx38.94  \: m

・ .━━━━━━━†━━━━━━━━━.・

<h3>Sixth</h3>

\qquad \sf  \dashrightarrow \:2×3.14 \times  5.1

\qquad \sf  \dashrightarrow \: \approx2×16.01 \: ft

\qquad \sf  \dashrightarrow \: \approx \: 32.02m

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

7 0
2 years ago
For a certain​ drug, the rate of reaction in appropriate units is given by Upper R prime (t )equalsStartFraction 2 Over t plus 1
Tems11 [23]

Answer:

a) 8.13

b) 4.10

Step-by-step explanation:

Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1

In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)

On integrating R'(t)

∫ (2/t+1 + 1/√t+1)dt

In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.

∫ (2/t+1 + 1/√t+1)dt

= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt

= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt

= 2ln(t+1) + 2(t+1)^1/2 + C

= 2ln(t+1) + 2√(t+1) + C

a) For total reactions from t = 1 to t = 12

When t = 1

R(1) = 2ln2 + 2√2

≈ 4.21

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

R(12) - R(1) ≈ 12.34-4.21

≈ 8.13

Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.

b) For total reactions from t = 12 to t = 24

When t = 12

R(12) = 2ln13 + 2√13

≈ 12.34

When t = 24

R(24) = 2ln25 + 2√25

≈ 16.44

R(12) - R(1) ≈ 16.44-12.34

≈ 4.10

Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10

3 0
3 years ago
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