5/8 as a decimal would be 0.625. :)
Answer:
4x-2y =42 is the required equation
Step-by-step explanation:
given equation is,
4x-2y -7=0---------eqn1
parallel equation of given equation is
4x -2y+k =0-------eqn 2
now passing it through (9,-3), we get,
4×9 + 2×3 +k = 0
or,36+6+k =0
or,42+k =0
or, k= -42
putting the value of k in eqn2
4x-2y - 42=0
4x-2y = 42
Answer:
Hi
Step-by-step What is a linear function in the form y= mx + b for the line passing through (4.5, -4.25) with y-intercept 2.5 yup help pleade
Answer:
For maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
Step-by-step explanation:
Let the length of the rectangular exercise run = l ft
and width of the run = w ft
Sinoman has to cover a rectangular exercise run from three sides with the fencing material,
So length of the material = (l + 2w) ft
l + 2w = 100
l = 100 - 2w --------(1)
Area of the rectangular area covered = Length × width
A = lw
A = w(100 - 2w) [(l = 100 - 2w)from equation (1)
For maximum area we find the derivative of area and equate it to zero.
![\frac{dA}{dw}=\frac{d}{dw}[w(100-2w)]](https://tex.z-dn.net/?f=%5Cfrac%7BdA%7D%7Bdw%7D%3D%5Cfrac%7Bd%7D%7Bdw%7D%5Bw%28100-2w%29%5D)

A' = 100 - 4w
For A' = 0
100 - 4w = 0
4w = 100
w = 25 ft
From equation (1)
l = 100 - 2w
l = 100 - 2×(25)
l = 50 ft
Therefore, for maximum area of the rectangular exercise run dimensions will be 50ft by 25ft.
C.) 3 points because you can't have 2 points on the same y axis line.