Answer:
Group b most likely has a lower mean age of salsa students
Step-by-step explanation:
Arithmetic Mean of the data is the average of a set of numerical values, calculated by adding them together and dividing by the number of terms in the set.
Here we are given with two groups that are Group A and Group B
both having total number of students = 20
Here the mean age of the data is addition of the all ages of different students divided by total number of students.
For group a
total age of the group = 3 × 5 + 4 × 10 + 6 × 17 + 4 × 24 + 3 × 29
= 15 + 40 + 102 + 96 + 87
=340
The mean age of salsa students= 340 ÷ 20 = 17
For group b
total age of the group = 6 × 7 + 3 × 10 + 4 × 14 + 5 × 16 + 2 × 21
= 42 + 30 + 56 + 80 + 42
=250
The mean age of salsa students= 250 ÷ 20 = 12.5
So the group b most likely has a lower mean age of salsa students
Learn more about Arithmetic Mean here - brainly.com/question/24688366
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hi
if x= 2+4y-5 then x-2 +5 = 4y so y = (x-2+5) /4 = ( x+3) /4
conclusion y = (x+3)/4
Answer:
The correct answer is NO. The best price to be charged is $3.75
Step-by-step explanation:
Demand equation is given by Q = 30 - 4P, where Q is the quantity of necklaces demanded and P is the price of the necklace.
⇒ 4P = 30 - Q
⇒ P = 
The current price of the necklace $10.
Revenue function is given by R = P × Q =
× ( 30Q -
)
To maximize the revenue function we differentiate the function with respect to Q and equate it to zero.
=
× ( 30 - 2Q) = 0
⇒ Q = 15.
The second order derivative is negative showing that the value of Q is maximum.
Therefore P at Q = 15 is $3.75.
Thus to maximize revenue the price should be $3.75.
Answer:
A and is michael michael reeves
Step-by-step explanation: