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NISA [10]
3 years ago
14

Helllo!!!! Can someone help me With this?? :))

Mathematics
2 answers:
Nastasia [14]3 years ago
5 0

Answer:

tggg ia 23 so answer is X I JUST TOOK THE TEST

Step-by-step explanation:

23

Yanka [14]3 years ago
5 0

Answer:

X=38 Z=63 Y=75

Step-by-step explanation:

i think

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6(14+x)=108, umm please help
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Answer:

X = 4

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4 0
3 years ago
9. Verizon offers a cell phone plan that includes a flat fee of $85 per month for the first phone and $7.50 a
Shalnov [3]

Answer:

4 phones

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Describe the end behavior of f(x) = - 2 ^ (x + 3) - 1
PilotLPTM [1.2K]

Answer: the answer is an equation

Step-by-step explanation:

4 0
3 years ago
the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2
Ksivusya [100]

Answer:

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1.

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is \frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1.

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,  

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by b^{2} = a^{2}(e^{2}  - 1) = 4[(\frac{5}{2} )^{2} -1] = 21 {Since e = \frac{5}{2} given}

Therefore, the equation of the given hyperbola will be  

\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1. (Answer)

6 0
3 years ago
A+ B = 30. A:B what is equivalent to 2:3
Paraphin [41]
2/3 and 12/18 are equivalent fractions, and 12+18 = 30 so the answer is 12:18 
5 0
3 years ago
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