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3 years ago

What is the perimeter of the figure?

Mathematics

2 answers:

Zarrin [17]3 years ago

4 0

Answer:

21.2 yd

Step-by-step explanation:

8 + 6 + 7.2 = 14 + 7.2 = 21.2

Radda [10]3 years ago

3 0

21.2 yd

To find the perimeter of a rectangle or square you have to add the lengths of all the four sides. x is in this case the length of the rectangle while y is the width of the rectangle.

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A square of area 36cm is cut to make two rectangles a and b the ratio of area a to b is 2:1 work ou the dimensions of rectangles

RoseWind [281]

Answer:

The dimensions of rectangle a are 6x4 and dimensions of rectangle b are 6x2.

Step-by-step explanation:

We are given a square with area 36 squared cm. Therefore, dimension of the square will be 6 cm.

The square is cut into two rectangles with areas in the ratio 2:1.

Let the dimensions of the rectangles be 6*a and 6*b. Therefore, we can set up the ratio of areas as:

$\frac{6a}{6b}=\frac{2}{1} \\a=2b$

Moreover, we can set the combined area of rectangles equal to the area of square to form another equation:

$6a+6b=36\\a+b=6$

Using substitution method, we can solve for 'a' and 'b' as shown below:

$2b+b=6\\3b=6\\b=2$

And

$a=2b\\a=2(2)\\a=4$

Therefore, dimensions of the two rectangles are 6x4 and 6x2, respectively.

8 0

3 years ago

Question 1

goldenfox [79]

Let t rep tail and h rep head

First tose= h or t

Second tose= h or t

Third tose= h or t

Counting the head and tail together

Then t= 3 and h=3

According to The formulae

3/6= 1/2

4 0

3 years ago

Solve for inequality -6<4x-2≤10

emmasim [6.3K]

Answer:

-1 < x ≤ 3

Step-by-step explanation:

group:

-6 < 4x - 2

4x - 2 ≤ 10

group:

-6 + 2 < (4x-2) + 2

(4x-2) + 2 ≤ 10 + 2

8 0

2 years ago

Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the

babymother [125]

Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

$d=\sqrt{(x_{2}-x_{1}) ^{2}+(y_{2}-y_{1}) ^{2} }$

DC:

D(-2,-1) C(-1,2)

$d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2} } \\d=\sqrt{10} =3.16$

CF:

C(-1,2) F(1,1)

$d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2} } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24$

F(1,1) E(2,-2)

$d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16$

E(2,-2) D(-2,-1)

$d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2} } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\$

3.16+2.24+3.16+4.12= 12.68

4 0

3 years ago

D = rt ; Solve for t

Nastasia [14]

Answer:

T stands for time

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers