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3 years ago

Please Help, I'm stuck on this question .

Mathematics

1 answer:

snow_lady [41]3 years ago

4 0

Answer:

24y^15 - 24y^10 + 7

Step-by-step explanation:

f(2y^5)

= 3(2y^5)^3 - 6(2y^5)^2 +7

= 3(8y^15) - 6(4y^10) + 7

= 24y^15 - 24y^10 + 7

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Solve the equation: k^2+5k+13=0

mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} \\$

From the question

a = 1 , b = 5 , c = 13

So we have

$k = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)} \\ = \frac{ - 5 \pm \sqrt{25 - 52} }{2} \\ = \frac{ - 5 \pm \sqrt{ - 27} }{2} \: \: \: \: \: \: \\ = \frac{ - 5 \pm3 \sqrt{3} \: i}{2} \: \: \: \: \: \:$

Separate the solutions

$k_1 = \frac{ - 5 + 3 \sqrt{3} \: i }{2} \: \: \: \: or \\ k_2 = \frac{ - 5 - 3 \sqrt{3} \: i}{2}$

The equation has complex roots

Separate the real and imaginary parts

We have the final answer as

$k_1 = - \frac{5}{2} + \frac{3 \sqrt{3} }{2} \: i \: \: \: \: or \\ k_2 = - \frac{5}{2} - \frac{3 \sqrt{3} }{2} \: i$

Hope this helps you

8 0

2 years ago

Write 187.023 in word form

riadik2000 [5.3K]

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3 years ago

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Which equation shows that the Pythagorean identity is true for 0 = 27? Select

oksano4ka [1.4K]

9514 1404 393

Answer:

B. 0^2 +1^2 = 1

Step-by-step explanation:

For θ = 2π, the trig identity is ...

sin(2π)² +cos(2π)² = 1

0² +1² = 1

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3 years ago

3x+3=108 PLSSS help Giving brainliest!!

jeka57 [31]

Answer:

x=35

Step-by-step explanation:

3x+3=108

3x=108-3

3x= 105

x= 105/3

x=35

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3 years ago

How do you write 9.51 x 10^-2 in standard form?

lbvjy [14]

Move the decimal point 2 places to the left answer: 0.0951

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3 years ago

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