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Mice21 [21]
2 years ago
8

Please Help, I'm stuck on this question .

Mathematics
1 answer:
snow_lady [41]2 years ago
4 0

Answer:

24y^15 - 24y^10 + 7

Step-by-step explanation:

f(2y^5)

= 3(2y^5)^3 - 6(2y^5)^2 +7

= 3(8y^15) - 6(4y^10) + 7

= 24y^15 - 24y^10 + 7

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Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
2 years ago
Write 187.023 in word form
riadik2000 [5.3K]
One hundred eighty-seven and twenty-three thousandths
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4 0
3 years ago
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Which equation shows that the Pythagorean identity is true for 0 = 27? Select
oksano4ka [1.4K]

9514 1404 393

Answer:

  B. 0^2 +1^2 = 1

Step-by-step explanation:

For θ = 2π, the trig identity is ...

  sin(2π)² +cos(2π)² = 1

  0² +1² = 1

3 0
3 years ago
3x+3=108 PLSSS help Giving brainliest!!
jeka57 [31]

Answer:

x=35

Step-by-step explanation:

3x+3=108

3x=108-3

3x= 105

x= 105/3

x=35

4 0
3 years ago
How do you write 9.51 x 10^-2 in standard form?
lbvjy [14]
Move the decimal point 2 places to the left answer: 0.0951
6 0
3 years ago
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