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DochEvi [55]
2 years ago
14

The dataset below shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks:

Mathematics
2 answers:
docker41 [41]2 years ago
5 0

Answer:  C: There is one outlier that indicates an unusually large number of cars were in the parking lot that day.

Step-by-step explanation:

OK so here is our data: 8 7 14 10 13 27 11 10 14 7 12 9 14 9

the simple thing to do it reorganize it from greatest to least

(7,8,10,11,12,14,14,14, 27) as you can see, most of the numbers are 1 or two values apart, but 27 is a whooping 12 more than 14

And since 27 is way more than the rest, we can conclude that the number of cars is unusually large

Katena32 [7]2 years ago
3 0
<span>C. On the 6th day, the cars parked in the lot were 27, which is the highest figure in the entire two weeks period. The other days the numbers varied with slight differences which is normal. However, the difference between the 6th day and the next day which recorded the highest number is very big. A difference of 13 cars is quiet large.</span>
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Step-by-step explanation:

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How do i factor 2x^2+11x+5
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You spin a spinner numbered 1 to 9, and roll a dice numbered 1 to 6. What is the probability of the compound event "getting an e
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Easy Sample Ap graphing 50pts! (Easy points!!) (ASAP) (URGENT) (Please check my other questions)​ Please
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Answer:

a)  See attachment 1.

b)  t² and D

c)  See attachment 2.

d)  g = 9.8 m/s² (1 d.p.)

Step-by-step explanation:

<h3><u>Part (a)</u></h3>

See attachment 1.  The line of best fit is shown in red.

<h3><u>Part (b)</u></h3>

The quantities the student should graph in order to produce a <u>linear relationship</u> between the two quantities are t² and D.

<h3><u>Part (c)</u></h3>

Make a table of values of t² and D:

\begin{array}{|l|l|l|l|l|l|}\cline{1-6} \rm t^2& 0.0196& 0.1024& 0.2116 & 0.3481& 0.3969\\\cline{1-6} \rm D & 0.10 & 0.50& 1.00 & 1.70 & 2.00\\\cline{1-6}\end{array}

<u>Plot</u> a graph of D against t² and draw a line of best fit (see attachment 2).

<h3><u>Part (d)</u></h3>

From inspection of the graph, the line of best fit passes through the origin (0, 0) and (0.1024, 5.0).  Therefore, use these two points to find the slope of the line:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{0.5-0}{0.1024-0}=4.8828125...\:\rm m/s^2

Therefore:

\rm \implies \dfrac{1}{2}g=4.8828125...\:\rm m/s^2

\rm \implies g=2 \cdot 4.8828125...\:\rm m/s^2

\rm \implies g=9.8\:\rm m/s^2\:(1\:d.p.)

5 0
1 year ago
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