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hodyreva [135]
3 years ago
7

Choose the measurement that is most precise.

Mathematics
2 answers:
SashulF [63]3 years ago
8 0

Answer:

12mm according to me......

Mamont248 [21]3 years ago
4 0

Answer:

A. 12 mm

Step-by-step explanation:

a million (milimeter) is smaller than a hundred (centimeter)

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take a hiset math test need help refresh with my study guide.and refresh help calculator how to use a scientific one​
n200080 [17]

Answer:

B) 4,320

Step-by-step explanation:

You would first find the volume of the triangular prism using this formula:

V = 1/2 x A x C x H

A = 3 C = 6 H = 24

V = 1/2 x 3 x 6 x 24 = 216 cubic feet

Since there are 20 pounds of snow per cubic foot, you multiply the cubic feet (216) by the pounds of snow per cubic foot (20):

216 x 20 = 4,320 pounds

4 0
3 years ago
Can someone help me with number 18 please
Akimi4 [234]
I got it its  this answer i used mathpapa for this
7 0
3 years ago
The half of the day from midday to midnight can be described as
Serjik [45]

Answer:

24hours divided by 2 is 12

Step-by-step explanation:

8 0
3 years ago
Help!! Find the area of the triangle.
grigory [225]

Answer:

Area = 60.0 units²

Step-by-step explanation:

First, let's find the height of the triangle using Pythagorean Theorem:

Height = √(11² - 8²)

= √57

Height = 7.5 (nearest tenth)

✔️Find the area:

Area = ½*base*height

Base = 2*8 = 16

Height = 7.5

Plug in the values

Area = ½*16*7.5

Area = 60.0 units² (nearest tenth)

3 0
2 years ago
Let f be the function given by f(x)= (x-1)(x^2-4)/x^2-a. For what positive values of a is f continuous for all real numbers x?
9966 [12]

Answer:

a =1 and a=4.

Step-by-step explanation:

The function is

f(x)=\frac{(x-1)(x^2-4)}{x^2-a}

If we want f(x) to be continuous the denominator needs to be different to 0, otherwise f(x) will be indeterminate.

Now, for a a positive real we have that x=\sqrt{a} will annulate the denominator, i.e

(\sqrt{a})^2-a = a-a = 0. But, if a = 1 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-1} = \frac{(x-1)(x^2-4)}{(x-1)(x+1)}=\frac{(x^2-4)}{x+1}

so, the value x=\sqrt{a} = \sqrt{1} = 1 won't annulate the denominator.

Now, for a = 4 we have:

f(x)=\frac{(x-1)(x^2-4)}{x^2-4} = x-1

so, the value x=\sqrt{a} = \sqrt{4} = 2 won't annulate the denominator.

In conclusion, for a=1 or a=1, the function will be continuos for all real numbers, since the denominator will never be 0.

4 0
3 years ago
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