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lawyer [7]
3 years ago
11

What percentage of females polled supported martinez

Mathematics
1 answer:
BigorU [14]3 years ago
7 0
The percentage of females that supported Martinez is 30 percent.
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PLEASE HELP ALSO WILL GET THE BRAINIEST ANSWER!!!! ALSO SHOW YOUR WORK!!!!
MAVERICK [17]
I=PRT
I=Interest
P=principal
R=rate in decimal
T=time in years

1year=12months
72months/12months=6 years
t=6

given
I=8925
P=35000
R=r
T=6


8925=35000*r*6
8925=210000*r
divide both sides by 210000
0.0425=r

the interest rate is 4.25%
6 0
3 years ago
Read 2 more answers
a group of friends shared 3 rolls of clay equally. if each student gor 1/2 of a roll of clay, how many students were in the grou
klemol [59]
6 students – 3 rolls of clay divided by each portion given to a student (0.5) equals 6, meaning only six students where able to receive some clay

8 0
3 years ago
What is the equation of the line that passes through (6,4) and (4,1)
Murrr4er [49]

Answer:

y = 3/2*x - 5

Step-by-step explanation:

Lets say that P1=(6,4) and P2=(4,1) and that the form of the equation must be y=m*x+b where m is the slope and b the independent variable. Then having two given points we can use the slope formula to find the slope value as:

P1=(x1,y1) and P2=(x2,y2)

slope formula --->   m=(y2-y1)/(x2-x1)

Replacing the given points --->    m=(1-4)/(4-6) = 3/2

then replacing the slope value obtained:

y = 3/2*x + b

Now lets find the value of b. For this we have to replace in the equation a point it can be P1 or P2, i will replace P2:

1 = 3/2*4 + b

1 = 6 + b

1 - 6 = b

-5 = b

therefore the line equation is:

y = 3/2*x - 5

3 0
3 years ago
Marking brainliest <br><br> Don’t know what to write for the last 2
nlexa [21]

Answer:

Business, management, marketing and technology.

Engineering, manufacturing and industrial technology.

i am not sure but i hope it will help you.

please mark me as brainlest.

4 0
3 years ago
Find x<br><br><br><br><br> Thanks for the help in advance!
Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

AH=2,\quad HB=6,\quad AC=x

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}

If we solve the first two equations for y squared, we have

y^2=x^2-4\\y^2=z^2-36

And we can deduce

z^2 = x^2+32

So that the third equation becomes

x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4

(we can't accept the negative root because negative lengths make no sense)

7 0
3 years ago
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