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AnnyKZ [126]
3 years ago
12

What is the degree measure of arc UTR

Mathematics
1 answer:
Paladinen [302]3 years ago
3 0

Answer:

212°

Step-by-step explanation:

arc UTR = 180+32 = 212°

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I really need help if anyone can help that would be great
Oliga [24]
Factor the denominator:

(3x-1)(x+2)

every time x=-2 (because of (x+2), it would cause a warp in the graph, and not have an input. that is the vertical asymptote.

since you have factor 3x-1 on top and bottom, in which the zero is 1/3, there would be no solution at x=1/3. it would be a hole.

the answer here is C.
5 0
3 years ago
If D is the midpoint of the segment AC and C is the midpoint of segment DB , what is the length of the segment AB , if AC = 3 cm
Juliette [100K]
<span>A midpoint divides a line or a segment into two equal parts. If D is the midpoint of the segment AC and C is the midpoint of segment DB, what is the length of the segment AB, if AC = 3 cm.</span>

 

If D is the midpoint of AC, then AD=DC

If C is the midpoint of DB, then DC=CB

If AC=3cm. then then DC-3/2=1.5

If DC=1.5 then CB is 1.5 also

AB=AC+CB

AB=3+1.5

AB=4.5

5 0
3 years ago
How many different 4-question geometry quizzes can a teacher make if there are 7 different problems to test on?.
stich3 [128]

Answer:

35 quizzes

Step-by-step explanation:

We need to determine how many ways we can choose 4 questions out of 7 to make the quizzes.

We do this by using the formula \displaystyle nCr=\frac{n!}{r!(n-r)!} which describes the number of ways we can choose r objects given n possible choices. So, if n=7 and r=4, then:

_4C_7=\frac{7!}{4!(7-4)!}\\\\_4C_7=\frac{7*6*5*4!}{4!*3!}\\\\_4C_7=\frac{210}{6}\\\\_4C_7=35

Hence, the teacher can make 35 different geometry quizzes.

3 0
2 years ago
Pre college need help with
kati45 [8]

Answer:

check online for more information

8 0
2 years ago
2x + y = 15 x + y = 10​
Artyom0805 [142]

Answer:

2x+y=15x+y=10

Consider the first equation. Subtract 15x from both sides.

2x+y−15x=y

Combine 2x and −15x to get −13x.

−13x+y=y

Subtract y from both sides.

−13x+y−y=0

Combine y and −y to get 0.

−13x=0

Divide both sides by −13. Zero divided by any non-zero number gives zero.

x=0

Consider the second equation. Insert the known values of variables into the equation.

15×0+y=10

Multiply 15 and 0 to get 0.

0+y=10

Anything plus zero gives itself.

3 0
2 years ago
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