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goldenfox [79]
3 years ago
8

Log3 (x+1)+log3 2x= log3 (3x+1)​

Mathematics
1 answer:
balu736 [363]3 years ago
8 0

Answer:

hello :  x=1

Step-by-step explanation:

look this solution  :

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Solve for s.<br><br> s<br> 3<br> = 2
tresset_1 [31]

S= 5? that's at the top of my head

5 0
3 years ago
Read 2 more answers
Compare. Write &lt;,&gt;, or =. (Example 1)
Vitek1552 [10]

Answer:ed44

Step-by-step explanation:

4 0
2 years ago
Math help @LIEMONDER
klio [65]
First picture)
I: 5x+2y=-4
II: -3x+2y=12

add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2

insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3

(-2,3)

question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs

insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults

insert adults into II:
33-8=childs
25=childs

so it's the last option

question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6

so it's the last option

question 8)
I: x+y=12
II: x-y=6

subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3

insert y into I:
x+3=12
x=9

(9,3)

question 9)
I: x+y=6
II: x=y+5

if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6

which is the second option :)
5 0
3 years ago
What is 6(7-2p) =12p+42
mafiozo [28]

answer:

p = 0

step-by-step explanation:

6 (7-2p) = 12p + 42

42 - 12p = 12p + 42

     +12p   +12p

_______________

42 = 24p + 42

-42            -42

_____________

0 = 24p

_    ___

24    24

0 = p


<em>hope this helps! ❤ from peachimin (aka kayla)</em>


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3 years ago
Conor has $200 available to buy software
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Don’t go to that link it is a virus it’s a bot doing that do not go to that link
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