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Tresset [83]
3 years ago
5

write the equation in standard form of the function with x intercepts at (4,0) and (-2,0) that has been reflected across the x a

xis with a vertical stretch of 3
Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

answer

-3x^{2} +6x + 24

explanation

since there are 2 x-intercepts, the lowest degree the function could possibly have is 2, so this could be the graph of a parabola

since our zeros are at x = 4 and x = -2, our factors are (x - 4) and (x + 2)

our equation so far is

(x - 4)(x + 2)

= x^2 -4x + 2x - 8

= x^{2} -2x - 8

since the function is reflected across the x-axis, multiply the equation by -1

-(x^{2} -2x - 8)

= -x^{2} +2x + 8

since the function has a vertical stretch of 3, multiply the equation by 3

3(-x^{2} +2x + 8)

= -3x^{2} +6x + 24

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