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Tresset [83]
3 years ago
5

write the equation in standard form of the function with x intercepts at (4,0) and (-2,0) that has been reflected across the x a

xis with a vertical stretch of 3
Mathematics
1 answer:
Anastaziya [24]3 years ago
3 0

answer

-3x^{2} +6x + 24

explanation

since there are 2 x-intercepts, the lowest degree the function could possibly have is 2, so this could be the graph of a parabola

since our zeros are at x = 4 and x = -2, our factors are (x - 4) and (x + 2)

our equation so far is

(x - 4)(x + 2)

= x^2 -4x + 2x - 8

= x^{2} -2x - 8

since the function is reflected across the x-axis, multiply the equation by -1

-(x^{2} -2x - 8)

= -x^{2} +2x + 8

since the function has a vertical stretch of 3, multiply the equation by 3

3(-x^{2} +2x + 8)

= -3x^{2} +6x + 24

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Determine whether the given linear equations are parallel, perpendicular, or neither.
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A. Perpendicular

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2 years ago
The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm.
Nat2105 [25]

Answer:

A) Maximum error = 170.32 cm³

B)Relative error = 0.0575

Step-by-step explanation:

A) Formula for circumference is: C = 2πr

Differentiating with respect to r, we have;

dC/dr = 2π

r is small, so we can write;

ΔC/Δr = 2π

So, Δr = ΔC/2π

We are told that ΔC = 0.5.

Thus; Δr = 0.5/2π = 0.25/π

Now, formula for Volume of a sphere is;

V(r) = (4/3)πr³

Differentiating with respect to r, we have;

dV/dr = 4πr²

Again, r is small, so we can write;

ΔS/Δr = 4πr²

ΔV = 4πr² × Δr

Rewriting, we have;

ΔV = ((2πr)²/π) × Δr

Since C = 2πr, we now have;

ΔV = (C²/π)Δr

ΔV will be maximum when Δr is maximum

Thus, ΔV = (C²/π) × 0.25/π

C = 82 cm

Thus;

ΔV = (82²/π) × 0.25/π

ΔV = 170.32 cm³

B) Formula for relative error = ΔV/V

Relative error = 170.32/((4/3)πr³)

Relative error = 170.32/((4/3)C³/8π³)

Relative errror = 170.32/((4/3)82³/8π³)

Relative error = 170.32/2963.744

Relative error = 0.0575

3 0
2 years ago
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