Find the distance between ( 1, 3) and (5, 6)

I poopoo myself how to clean

anyanavicka [17]

Answer:

you clean!?

Step-by-step explanation:

I just lick it

3 0

3 years ago

Read 2 more answers

Answer the two questions below. THANKS!!

vivado [14]

Problem 1

We're given that angle A = angle B. Also that angle B = angle C.

By the transitive property, we can say angle A = angle C.

So basically all three angles are equal to one another. Let's call that unknown angle x.

For any triangle, the three angles always add to 180, so,

x+x+x = 180

3x = 180

x = 180/3

x = 60

That proves angles A,B, and C are each 60 degrees. This triangle is considered equiangular since all angles are the same. Furthermore, the triangle is also considered equilateral meaning all sides are the same. The term equilateral is more widely used, so I'd go with that term if you could only pick one.

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Problem 2

As mentioned in problem 1, the three angles of a triangle add to 180

A+B+C = 180

A+B+90 = 180

A+B+90-90 = 180-90

A+B = 90

This shows A and B are complementary angles. Complementary angles by definition add to 90 degrees.

5 0

3 years ago

Consider the equation and its solution.

AVprozaik [17]

Answer:

The correct answer is C. 2.

Step-by-step explanation:

To solve this problem, we should begin with the second step and work backwards in order to find the unknown value. If given the equation -15x + 30 = 25, we should factor out a -15 to simplify. This method is shown below.

-15x + 30 = 25

-15(x-2) = 25

We know this is correct because if we redistribute the -15 through the parentheses using the distributive property, we would get our original equation again. In other words, this answer is confirmed by the fact that -15 * -2 equals positive 30.

However, we need to look closely at the question that is asked. The box that we must fill in is already preceded by a negative sign, thus the correct answer is C. 2.

We can check our work by replacing the box with the number 2, getting -15(x-2) + 30 = 25, which was the equation we got earlier.

Hope this helps!

5 0

3 years ago

What is −1/3−1 2/3=?

ra1l [238]

The answer to <span>−1/3−1 2/3= is -2
ANSWER: </span><span>−1/3−1 2/3= -2

I hope I helped.
Have a good day.</span>

7 0

4 years ago

Please please please i need help !!!

Stella [2.4K]

Answer: Choice B

h(c) = 1 for at least one c between -3 and 4

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Explanation:

Draw an xy axis system. Plot the points (-3,-1) and (4,2) on this grid. These points come from the fact that h(-3) = -1 and h(4) = 2. These are the endpoints of the h(x) function.

Next, draw horizontal lines through both points. Also, draw vertical lines through the two points as well. A rectangle will form.

The region inside this rectangle is all we care about.

We're told that h(x) has endpoints mentioned earlier, and h(x) is continuous, so that means we have some curve or line through the two points. One such example is shown below. There are infinitely many possible curves to draw out as long as they stay in the rectangle.

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After you have your h(x) function curve drawn, draw a horizontal line through y = 1 on the y axis. This is the dashed line in the diagram below.

This horizontal line crosses the green h(x) curve at one point or more. In my example, it does so at one point only. However, you could easily draw h(x) so that it crosses y = 1 as many times as you want (just have it squiggle up and down multiple times).

This shows that h(c) = 1 is possible when $-3 \le c \le 4$ . Here c is playing the role of x since it is the input of a function. The h(c) is the output, so that's the y value.

This says that for some input between -3 and 4, it's possible to get an output of 1.

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Here's a real world example of the intermediate value theorem.

Let's say the endpoints are A and B, and they are two towns.

The h(x) curve is a road connecting the towns.

To go from A to B, or vice versa, we need to cross over some border that is between the towns. The border in this case is the dashed horizontal line in the diagram.

side note: A special use of the intermediate value theorem is to show that a root exists on some interval (if you know the function changes between positive to negative, or vice versa).

7 0

3 years ago