Answer:
Suppose that a couple invested $50,000 in an account when their child was born, to prepare for the child's college education. If the average interest rate is 4.4% compounded annually, ( A ) Give an exponential model for the situation, and ( B ) Will the money be doubled by the time the child turns 18 years old?
( A ) First picture signifies the growth of money per year.
( B ) Yes, the money will be doubled as it's maturity would be $108,537.29.
a = p(1 + \frac{r}{n} ) {}^{nt}a=p(1+
n
r
)
nt
a = 50.000.00(1 + \frac{0.044}{1} ) {}^{(1)(18)}a=50.000.00(1+
1
0.044
)
(1)(18)
a = 50.000.00(1 + 0.044) {}^{(1)(18)}a=50.000.00(1+0.044)
(1)(18)
a = 50.000.00(1.044) {}^{(18)}a=50.000.00(1.044)
(18)
50,000.00 ( 2.17074583287910578440507440 it did not round off as the exact decimal is needed.
a = 108.537.29a=108.537.29
Step-by-step explanation:
Hope This Help you!!
Answer:
y
=1
/3
x
+
14
/3
Step-by-step explanation:
Answer:
8! 8x8=64 lol
Step-by-step explanation:
Hope this helps, And have a good day!
Answer:
First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable
Step-by-step explanation:
This is a sequence because the points form a straight line. The expression is: t(n) = 30 + 2x, x is number of weeks. On her 18th birthday, that is 8 years after her 10th. that means 416 weeks have passed since her 10th birthday. Plug 416 into the equation to get: t(416) = 30 + 2(416) = $862. She will have $862 to Spend.
