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maria [59]
3 years ago
15

Find the distance between ( 1, 3) and (5, 6)

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

Step-by-step explanation:

1, 3

5, 6

subtract

4 x

3 y

4^2 + 3^2 = 5^2

so the distance is 5 units

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8.75 is 0.5% of what number
Otrada [13]

Answer:

1750

Step-by-step explanation:

I put it in an image

but multiplyng it would have been the opposite.

and it would be 0.5% of 8.75 is what.

3 0
4 years ago
Mathematicians, please check my work
kodGreya [7K]
The answer that you said is right. I totally agree with you.
3 0
3 years ago
8.5 rounded to nearest tenth
melomori [17]
The answer is 9.0 because 8.5 is above 5 and to the nearest tenth it would be 9.0
4 0
3 years ago
What is the value of x in the equation (x + 12) = (x + 14) – 3?
vodomira [7]
(x + 12) = (x + 14) - 3

subtract 12 from each side

x = x + 14 - 3 - 12

Now if we subtract x from each side we see that x - x = 0.  Combine the terms left over and we have -1, so

0 = -1

The answer is NO SOLUTION
6 0
3 years ago
Read 2 more answers
At time​ t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m. a. Find t
larisa [96]

Answer:

Step-by-step explanation:

Given that at time t, the position of a body moving along the​ s-axis is sequalsnegative t cubed plus 15 t squared minus 72 t m

i.e. s(t) = -t^3+15t^2-72 t

Velocity is nothing but s'(t) = derivative of s

and acceleration is s"(t) = derivative of v(t)

v(t) = -3t^2+30t-72\\=-3(t^2-10t+24)\\= -3(t-6)(t-4)

a) v(t) =0 when t = 4 or 6

b) a(t) = -6t+30

a(t) =0 when t =5

c) Distance travelled by the body from 0 to 5 would be

s(5)-s(0)\\= -5^3+15(5^2)-72(5)\\= -125+375-360\\=-110

i.e. 110 miles (distance cannot be negative)

3 0
3 years ago
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