Find the distance between ( 1, 3) and (5, 6)

Mathematics

1 answer:

Mademuasel [1]2 years ago

5 0

Answer:

Step-by-step explanation:

1, 3

5, 6

subtract

4 x

3 y

4^2 + 3^2 = 5^2

so the distance is 5 units

You might be interested in

Enter a range of values for x please help me

Brums [2.3K]

Answer:

-5 < x < 9

Step-by-step explanation:

By Hinge theorem,

"If two sides of a triangle are congruent to the two sides of another triangle, and the included angle of one triangle is larger than the included angle of the second, then the 3rd side of triangle one will be larger than the third side of the second"

23 > 21

Therefore, 42° > (3x + 15)°

42° - 15° > 3x

27 > 3x

9 > x

And (3x + 15) > 0

3x > -15

x > -5

Therefore, range for x will be,

-5 < x < 9

4 0

2 years ago

What is (99/100)^101 times (100/99)^100?

sineoko [7]

Answer:

99/100

Step-by-step explanation:

First of all recall that

$a^n\cdot b^n =(ab)^n$

Now we we will try to apply that formula for $a=99/100$ and $b=100/99$ .

First rewrite $(99/100)^{101}=(99/100)\times (99/100)^{100}$

Now

$(99/100)\times (99/100)^{100}\times (100/99)^{100}\\=(99/100)\times ((99/100)\times (100/99))^{100}\\=(99/100)\times 1^{100}\\=(99/100)\times 1\\=99/100$