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salantis [7]
3 years ago
14

Find the median, lower quartile, and upper quartile for the set of data.

Mathematics
1 answer:
Irina-Kira [14]3 years ago
5 0

Answer:

The median is 2 lower quartile is 11 and upper quartile is 6

Step-by-step explanation:

hope this helps

You might be interested in
f the dean wanted to estimate the proportion of all students receiving financial aid to within 3% with 99% reliability, how many
Oksanka [162]

Answer:

n=1849

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 99% of confidence, our significance level would be given by \alpha=1-0.99=0.01 and \alpha/2 =0.005. And the critical value would be given by:

z_{\alpha/2}=-2.58, z_{1-\alpha/2}=2.58

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Assuming that the proportion is estimated \hat p =0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{2.58})^2}=1849  

And rounded up we have that n=1849

7 0
3 years ago
Subtract:<br> 8 1b, 12 oz. - 5 lb, 5 oz.
Sedbober [7]

Answer:

wouldn't it be 3lb and 7oz

6 0
2 years ago
Learning Task Find the perimeter and area of each figure<br>Perimeter<br>Area<br>om<br>som<br>So​
nexus9112 [7]

Answer:

Step-by-step explanation:

1. Perimeter: 8cm + 8cm + 3cm + 3cm = 22cm

Area: 8cm x 3cm = 24cm

2. Perimeter: 5m + 5m + 5m + 5m = 20m

Area: 5m x 5m = 25m

3. Perimeter: 4m + 4m + 18m + 18m = 44m

Area: 4m x 18m = 72m

6 0
3 years ago
Oliver removed 56 marbles from his marble
krok68 [10]
ANSWER:
Total marbles =56
Number of groups =8
Therefore number of marbles in each group =56/8
= 7 marbles in each group.
HOPE IT HELPS!!!!
PLEASE MARK BRAINLIEST !!!!
5 0
3 years ago
Read 2 more answers
3<br> Solve<br> у<br> 4<br> = 10.5<br> Help asap
aksik [14]

Answer:

y=2.625

Step-by-step explanation:

3 0
3 years ago
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