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3 years ago

Find the median, lower quartile, and upper quartile for the set of data.

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer:

The median is 2 lower quartile is 11 and upper quartile is 6

Step-by-step explanation:

hope this helps

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PLZ ANSWER <3

Oksi-84 [34.3K]

Answer:

hang on give me a sec to edit this

it is.

8 0

2 years ago

Read 2 more answers

1) Use power series to find the series solution to the differential equation y'+2y = 0 PLEASE SHOW ALL YOUR WORK, OR RISK LOSING

iogann1982 [59]

$y=\displaystyle\sum_{n=0}^\infty a_nx^n$

then

$y'=\displaystyle\sum_{n=1}^\infty na_nx^{n-1}=\sum_{n=0}^\infty(n+1)a_{n+1}x^n$

The ODE in terms of these series is

$\displaystyle\sum_{n=0}^\infty(n+1)a_{n+1}x^n+2\sum_{n=0}^\infty a_nx^n=0$

$\displaystyle\sum_{n=0}^\infty\bigg(a_{n+1}+2a_n\bigg)x^n=0$

$\implies\begin{cases}a_0=y(0)\\(n+1)a_{n+1}=-2a_n&\text{for }n\ge0\end{cases}$

We can solve the recurrence exactly by substitution:

$a_{n+1}=-\dfrac2{n+1}a_n=\dfrac{2^2}{(n+1)n}a_{n-1}=-\dfrac{2^3}{(n+1)n(n-1)}a_{n-2}=\cdots=\dfrac{(-2)^{n+1}}{(n+1)!}a_0$

$\implies a_n=\dfrac{(-2)^n}{n!}a_0$

So the ODE has solution

$y(x)=\displaystyle a_0\sum_{n=0}^\infty\frac{(-2x)^n}{n!}$

which you may recognize as the power series of the exponential function. Then

$\boxed{y(x)=a_0e^{-2x}}$

7 0

3 years ago

If mal buys $245. And Zack buys $567.who's cost more and why.

erica [24]

Well Zack's cost more because, he paid $567.00 for whatever he bought, while Mal paid $245.00 for whatever he bought.

5 0

3 years ago

Read 2 more answers

A bag contains colored tiles.

KiRa [710]

Answer:

0.5

Step-by-step explanation:

Add everything together 33+66+33 = 132

Then 66/132, = 1/2 or 0.5

6 0

3 years ago

Read the questions and choose the best answer.

Arte-miy333 [17]

Where’s the questions ?

8 0

2 years ago