All categories

3 years ago

Find the median, lower quartile, and upper quartile for the set of data.

Mathematics

1 answer:

Irina-Kira [14]3 years ago

5 0

Answer:

The median is 2 lower quartile is 11 and upper quartile is 6

Step-by-step explanation:

hope this helps

You might be interested in

Use Euler's method with step size 0.2 to estimate y(1), where y(x) is the solution of the initial-value problem y' = x2y − 1 2 y

irina [24]

Answer:

Therefore the value of y(1)= 0.9152.

Step-by-step explanation:

According to the Euler's method

y(x+h)≈ y(x) + hy'(x) ....(1)

Given that y(0) =3 and step size (h) = 0.2.

$y'(x)= x^2y(x)-\frac12y^2(x)$

Putting the value of y'(x) in equation (1)

$y(x+h)\approx y(x) +h(x^2y(x)-\frac12y^2(x))$

Substituting x =0 and h= 0.2

$y(0+0.2)\approx y(0)+0.2[0\times y(0)-\frac12 (y(0))^2]$

$\Rightarrow y(0.2)\approx 3+0.2[-\frac12 \times3]$ [∵ y(0) =3 ]

$\Rightarrow y(0.2)\approx 2.7$

Substituting x =0.2 and h= 0.2

$y(0.2+0.2)\approx y(0.2)+0.2[(0.2)^2\times y(0.2)-\frac12 (y(0.2))^2]$

$\Rightarrow y(0.4)\approx 2.7+0.2[(0.2)^2\times 2.7- \frac12(2.7)^2]$

$\Rightarrow y(0.4)\approx 1.9926$

Substituting x =0.4 and h= 0.2

$y(0.4+0.2)\approx y(0.4)+0.2[(0.4)^2\times y(0.4)-\frac12 (y(0.4))^2]$

$\Rightarrow y(0.6)\approx 1.9926+0.2[(0.4)^2\times 1.9926- \frac12(1.9926)^2]$

$\Rightarrow y(0.6)\approx 1.6593$

Substituting x =0.6 and h= 0.2

$y(0.6+0.2)\approx y(0.6)+0.2[(0.6)^2\times y(0.6)-\frac12 (y(0.6))^2]$

$\Rightarrow y(0.8)\approx 1.6593+0.2[(0.6)^2\times 1.6593- \frac12(1.6593)^2]$

$\Rightarrow y(0.6)\approx 0.8800$

Substituting x =0.8 and h= 0.2

$y(0.8+0.2)\approx y(0.8)+0.2[(0.8)^2\times y(0.8)-\frac12 (y(0.8))^2]$

$\Rightarrow y(1.0)\approx 0.8800+0.2[(0.8)^2\times 0.8800- \frac12(0.8800)^2]$

$\Rightarrow y(1.0)\approx 0.9152$

Therefore the value of y(1)= 0.9152.

4 0

3 years ago

60in in feet <br> Pls help fast !

PolarNik [594]

Answer:

5 feet

Step-by-step explanation:

Divide 60 inches by 12

Your answer is 5 feet.

Hope this helped :)

6 0

3 years ago

The bake stars started with 3.5 pounds of power pasta. Luis and Marlana by 0.83 pounds. how much is left over?

Salsk061 [2.6K]

Answer:

2.67

Step-by-step explanation:

They are asking for the total poundage of power pasta after some is removed. This means we subtract the amount removed from the original amount.

Hope this helps you

7 0

3 years ago

Square A has a side length of (2x-7) and Square B has a side length of (-4x+18). How much bigger is the perimeter of Square B th

dusya [7]

4(2x-7)=8x-28
4(-4x+18)=-16x+72
(8x-28)-(-16x+73)

24x+45

8 0

4 years ago

5(x-4)=15<br> find out what x is

Digiron [165]

Answer:

Step-by-step explanation:

7-4=3

5×3=15

plz mark brainliest

4 0

3 years ago

Read 2 more answers