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Strike441 [17]
3 years ago
13

A pair of boots originally cost $124. Now they are on sale for 75% of the original price. What is the sale price of the boots?

Mathematics
2 answers:
Serggg [28]3 years ago
8 0
Im not sure but im thinking the answer would be:

The sale price is $93(sorry if im wrong)

cricket20 [7]3 years ago
5 0
<span>easy 124 times .75 = 93 so the new sale price is $93 </span>
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The difference of four times a number and 5<br> is 39. Find the number.
EastWind [94]
The difference of four times a number and 5 is 39 can be expressed algebraically as:

4x - 5 = 39

Now, we can solve for x.

Add 5 to both sides:

4x - 5 + 5 = 39 + 5

4x = 44

Divide both sides by 4 to solve for x:

4x/4 = 44/4

x = 11

Please mark my answers as the Brainliest if you find this helpful :)
8 0
3 years ago
What is the smallest integer $n$, greater than $1$, such that $n^{-1}\pmod{130}$ and $n^{-1}\pmod{231}$ are both defined?
olasank [31]

First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.

We have

130 = 2 • 5 • 13

231 = 3 • 7 • 11

so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.

To verify the claim, we try to solve the system of congruences

\begin{cases} 17x \equiv 1 \pmod{130} \\ 17y \equiv 1 \pmod{231} \end{cases}

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:

130 = 7 • 17 + 11

17 = 1 • 11 + 6

11 = 1 • 6 + 5

6 = 1 • 5 + 1

⇒   1 = 23 • 17 - 3 • 130

Then

23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)

so that x = 23.

Repeat for 231 and 17:

231 = 13 • 17 + 10

17 = 1 • 10 + 7

10 = 1 • 7 + 3

7 = 2 • 3 + 1

⇒   1 = 68 • 17 - 5 • 231

Then

68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)

so that y = 68.

3 0
3 years ago
Please help me. I will give out brainliest.
strojnjashka [21]

area of quadrilateral (rhombus)=<u>4square units</u>

<u>:</u>

Solution given:

diagonal 1:AC=2 unit

diagonal 2:BD=4 unit

it looks like a rhombus

so

area of quadrilateral (rhombus)

=½*(diagonal 1*diagonal2)=½(2*4)=4 square units

8 0
3 years ago
Read 2 more answers
15 POINTS (Will MARK BRAINLIEST) Simply theses problems
stiks02 [169]

Answer:

Part A: 108

Part B: 125

Part C: 1.71 x 10^-4

Part D: 0.2

Part E: 0.040

Sorry for the wait, laptop is being slow :/

I hope this helps.

4 0
3 years ago
A chef had 7 potatoes how many bowls of mashed potatoes could he make if each bowl used one-fifth of a potato
12345 [234]

Answer:

35 bowls of mashed potatoes.

Step-by-step explanation:

To make a bowl of mashed potatoes, the chef uses one-fifth of a potato.

To use up one potato, he will make 5 bowls of mashed potatoes from it:

1 / (1/5) = 5 bowls of mashed potatoes.

With the 7 potatoes he has, he can make 7 x 5 bowls = 35 bowls of mashed potatoes.

4 0
3 years ago
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