The difference of four times a number and 5 is 39 can be expressed algebraically as:
4x - 5 = 39
Now, we can solve for x.
Add 5 to both sides:
4x - 5 + 5 = 39 + 5
4x = 44
Divide both sides by 4 to solve for x:
4x/4 = 44/4
x = 11
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First of all, the modular inverse of n modulo k can only exist if GCD(n, k) = 1.
We have
130 = 2 • 5 • 13
231 = 3 • 7 • 11
so n must be free of 2, 3, 5, 7, 11, and 13, which are the first six primes. It follows that n = 17 must the least integer that satisfies the conditions.
To verify the claim, we try to solve the system of congruences

Use the Euclidean algorithm to express 1 as a linear combination of 130 and 17:
130 = 7 • 17 + 11
17 = 1 • 11 + 6
11 = 1 • 6 + 5
6 = 1 • 5 + 1
⇒ 1 = 23 • 17 - 3 • 130
Then
23 • 17 - 3 • 130 ≡ 23 • 17 ≡ 1 (mod 130)
so that x = 23.
Repeat for 231 and 17:
231 = 13 • 17 + 10
17 = 1 • 10 + 7
10 = 1 • 7 + 3
7 = 2 • 3 + 1
⇒ 1 = 68 • 17 - 5 • 231
Then
68 • 17 - 5 • 231 ≡ = 68 • 17 ≡ 1 (mod 231)
so that y = 68.
area of quadrilateral (rhombus)=<u>4square units</u>
<u>:</u>
Solution given:
diagonal 1:AC=2 unit
diagonal 2:BD=4 unit
it looks like a rhombus
so
area of quadrilateral (rhombus)
=½*(diagonal 1*diagonal2)=½(2*4)=4 square units
Answer:
Part A: 108
Part B: 125
Part C: 1.71 x 10^-4
Part D: 0.2
Part E: 0.040
Sorry for the wait, laptop is being slow :/
I hope this helps.
Answer:
35 bowls of mashed potatoes.
Step-by-step explanation:
To make a bowl of mashed potatoes, the chef uses one-fifth of a potato.
To use up one potato, he will make 5 bowls of mashed potatoes from it:
1 / (1/5) = 5 bowls of mashed potatoes.
With the 7 potatoes he has, he can make 7 x 5 bowls = 35 bowls of mashed potatoes.