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2 years ago

7

Simplify x X x^5 divided by x^2 X x

2 answers:

Alecsey [184]2 years ago

7 0

Answer:

$\huge\boxed{(x\cdot x^5):(x^2\cdot x)=x^3}$

Step-by-step explanation:

$(x\cdot x^5):(x^2\cdot x)\qquad|\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{1+5}:x^{2+1}=x^6:x^3\qquad|\text{use}\ a^n:a^m=a^{n-m}\\\\=x^{6-3}=x^3$

kobusy [5.1K]2 years ago

5 0

Answer:

X × X^5 ÷ X^2 ×X

X^3

because the same variable can be cancelled.

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Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

$y=Ce^{kt}$ . We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is $\frac{dy}{dt}$ . Thus, the change in the concentration of salt is found in

$\frac{dy}{dt}=$ inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

$3(\frac{y}{400})$

Therefore,

$\frac{dy}{dt}=0-3(\frac{y}{400})$ or just

$\frac{dy}{dt}=-\frac{3y}{400}$ and in terms of time,

$-\frac{3t}{400}$

Thus, our equation is

$y=28e^{-\frac{3t}{400}$ and filling in 16 for the number of minutes in t:

y = 24.834 pounds of salt

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3 years ago

Find the midpoint of the line segment with the given endpoints: (-1, -6) and (-6, 5).

Vikentia [17]

Answer:

Step-by-step explanation:

First, we will find the midpoint for the x - coordinate first.

Midpoint (x) = $\frac{-1+(-6)}{2} \\=\frac{-1-6}{2} \\=\frac{-7}{2} \\=-3.5$

Now we will find the midpoint for the y - coordinate.

Midpoint (y) = $\frac{-6+5}{2} \\=\frac{-1}{2} \\=-0.5$

Therefore from these 2 values we know that the midpoint of this 2 points is (-3.5,-0.5)

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1 year ago

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ikadub [295]

Answer:

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Step-by-step explanation:

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3 years ago

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Delvig [45]

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3 years ago

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4. When finding the intersection of two lines from both Algebra I and Geometry, you first "set the linear

Masteriza [31]

<u><em>Answer:</em></u>

The intersection point is (-4,-19)

<u><em>Explanation:</em></u>

<u>The two given equations are:</u>

y = 5x + 1

y = 2x - 11

<u>To find the intersection point, we will start by equating the two given equations and solving for x</u>

<u>This is done as follows:</u>

5x + 1 = 2x - 11

5x - 2x = -11 - 1

3x = - 12

x = -4

<u>Then, we will use the x and substitute in any of the equations to get the value of y</u>

<u>Using the first equation:</u>

y = 5x + 1 = 5(-4) + 1 = -19

<u>Check using the second equation:</u>

y = 2x - 11 = 2(-4) - 11 = -19 ................? checked

<u>Therefore:</u>

The intersection point between the two given equations is (-4,-19)

Hope this helps :)

3 0

2 years ago