This is one of those problems where you'll sink like a rock if
you allow yourself to be blinded by all the useless, unnecessary,
irrelevant information in the first paragraph.
The ONLY information you need is:
-- You're chartering a bus for 1 day.
-- It costs $780 .
That's ALL .
(You don't even need to know that the bus has 55 seats.
You might need that for #8 - #12, but not for #6 or #7.)
_________________________
If the people on the trip are going to share the cost of the bus,
then the cost of each share depends on the number of people.
Less people ==> each one pays more.
More people ==> each one pays less.
Just like everybody in the office sharing the cost of
a birthday gift for the boss.
#6 and #7 should really be done in the reverse order ...
do #7 before you worry about #6.
Before you can fill in the table in #6, you absolutely need
to have the equation, whether or not you realize it.
The total cost is fixed . . . It's $780 .
If 2 people go on the trip, each one pays 780 / 2 .
If 3 people go on the trip, each one pays 780 / 3 .
If 4 people go on the trip, each one pays 780 / 4 .
If 5 people go on the trip, each one pays 780 / 5 .
.
.
If 10 people go on the trip, each one pays 780 / 10 .
.
.
If 20 people go on the trip, each one pays 780 / 20 .
.
.
If ' n ' people go on the trip, each one pays 780 / n .
.
. until the bus is full ...
.
If 55 people go on the trip, each one pays 780 / 55 .
.
If 56 people go on the trip, then you need another bus,
and it gets more complicated.
But up to 55, the price per person is (780 / the number of people).
<span> #7). P = 780 / n .
</span>Now, filling in the table in #6 is a piece 'o cake.<span>
</span>5 people. . . . . . . 780 / 5
10 people . . . . . 780 / 10
15 people . . . . . 780 / 15
20 people . . . . . 780 / 20
.
.
etc.
Just don't go past 55 people. The equation changes after that.
For ANY number of people, even hundreds, and ANY number
of buses, I think the equation looks something like this:
P = (785/n) · [ 1 + int(n/56) ] .
' int ' means ' the greatest integer in ... ', that is,
' throw away the fractional part of the quotient,
and use only the whole number '.
Answer:
x=1
Step-by-step explanation:
First you would do the parentheses.
So, 4 x X= 4x
4x2=8
4x+8=2x+10
subtract 2x on both sides
2x+8=10
subtract 8 from both sides
2x=2
x=1
Step-by-step explanation:
<h3><u>Given :-</u></h3>
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
<h3>
<u>Required To Prove :-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Proof :-</u></h3>
On taking LHS
[1+(1/Tan²θ)] + [ 1+(1/Cot²θ)]
We know that
Tan θ = 1/ Cot θ
and
Cot θ = 1/Tan θ
=> (1+Cot²θ)(1+Tan²θ)
=> (Cosec² θ) (Sec²θ)
Since Cosec²θ - Cot²θ = 1 and
Sec²θ - Tan²θ = 1
=> (1/Sin² θ)(1/Cos² θ)
Since , Cosec θ = 1/Sinθ
and Sec θ = 1/Cosθ
=> 1/(Sin²θ Cos²θ)
We know that Sin²θ+Cos²θ = 1
=> 1/[(Sin²θ)(1-Sin²θ)]
=> 1/(Sin²θ-Sin²θ Sin²θ)
=> 1/(Sin²θ - Sin⁴θ)
=> RHS
=> LHS = RHS
<u>Hence, Proved.</u>
<h3><u>Answer:-</u></h3>
[1+(1/Tan²θ)]+[1+(1/Cot²θ)] = 1/(Sin²θ-Sin⁴θ)
<h3><u>Used formulae:-</u></h3>
→ Tan θ = 1/ Cot θ
→ Cot θ = 1/Tan θ
→ Cosec θ = 1/Sinθ
→ Sec θ = 1/Cosθ
<h3><u>Used Identities :-</u></h3>
→ Cosec²θ - Cot²θ = 1
→ Sec²θ - Tan²θ = 1
→ Sin²θ+Cos²θ = 1
Hope this helps!!
M would be 1 because 1 x 10 would be 10 and 1 x 2 would be 2. 10-2=8! I hope it helps! chyna♡
