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masya89 [10]
3 years ago
7

Simplify x X x^5 divided by x^2 X x

Mathematics
2 answers:
Alecsey [184]3 years ago
7 0

Answer:

\huge\boxed{(x\cdot x^5):(x^2\cdot x)=x^3}

Step-by-step explanation:

(x\cdot x^5):(x^2\cdot x)\qquad|\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=x^{1+5}:x^{2+1}=x^6:x^3\qquad|\text{use}\ a^n:a^m=a^{n-m}\\\\=x^{6-3}=x^3

kobusy [5.1K]3 years ago
5 0

Answer:

X × X^5 ÷ X^2 ×X

X^3

because the same variable can be cancelled.

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Please help mehhh Thank you! :)
vivado [14]
Parentheses first -4+-8= -12(1)= -12
= -12
4 0
3 years ago
Drag each graph to show if the system of linear equations it represents will have no solutions, one solution at (2,6), one solut
hjlf

Answer:

see the explanation

Step-by-step explanation:

<u><em>Verify each case</em></u>

Part 1) The graph show two identical lines, then the system has infinitely many solutions

Part 2) The graph show two perpendicular lines.

Remember that the solution of the system is the intersection point both graphs

The intersection point is (2,6)

therefore

The system has one solution at (2,6)

Part 3) The graph show two intersecting lines at (-6,-2)

Remember that the solution of the system is the intersection point both graphs

The intersection point is (-6,-2)

therefore

The system has one solution at (-6,-2)

8 0
3 years ago
Connecticut families were asked how much they spent weekly on groceries. Using the following data, construct and interpret a 95%
Amanda [17]

Answer:

The 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

Step-by-step explanation:

The data for the amount of money spent weekly on groceries is as follows:

S = {210, 23, 350, 112, 27, 175, 275, 50, 95, 450}

<em>n</em> = 10

Compute the sample mean and sample standard deviation:

\bar x =\frac{1}{n}\cdot\sum X=\frac{ 1767 }{ 10 }= 176.7

s= \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }       = \sqrt{ \frac{ 188448.1 }{ 10 - 1} } \approx 144.702

It is assumed that the data come from a normal distribution.

Since the population standard deviation is not known, use a <em>t</em> confidence interval.

The critical value of <em>t</em> for 95% confidence level and degrees of freedom = n - 1 = 10 - 1 = 9 is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (10-1)}=t_{0.025, 9}=2.262

*Use a <em>t</em>-table.

Compute the 95% confidence interval for the population mean amount spent on groceries by Connecticut families as follows:

CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\ \frac{s}{\sqrt{n}}

     =176.7\pm 2.262\cdot\ \frac{144.702}{\sqrt{10}}\\\\=176.7\pm 103.5064\\\\=(73.1936, 280.2064)\\\\\approx (73.20, 280.21)

Thus, the 95% confidence interval for the population mean amount spent on groceries by Connecticut families is ($73.20, $280.21).

7 0
3 years ago
Is it 80% 70% 50% 60%
nexus9112 [7]

Answer:

50%

Step-by-step explanation:

As there are only two sides of the coin it will be 50% each.

7 0
3 years ago
Which of the following choices represents the area of the figure below?
Agata [3.3K]

Answer:

x^2-16

Step-by-step explanation:

A= (b)(h)

A= (x+4)(x-4)

x^2-4^2

x^2-16

6 0
2 years ago
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