We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem.
Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.
Find the Volume
Volume
l = 27 cm
w = 14 cm
h = 22 cm
V = 27 *14 * 22
V = 8316 cm^3
Find the surface area
SA = 2*l*w + 2*l*h + 2*w*h
SA = 2*27*14 + 2*27*22 + 2*14*22
SA = 756 + 1188 + 616
SA = 2558
Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.
Another way to do this is to consider a cube which might give you a more useful result.
s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2


That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.
Step-by-step explanation:
✲ 
Remove the unnecessary brackets :
⇢ 
Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.
⇢ 
⇢ 

Hope I helped ! ♡
Have a wonderful day / night ! ツ
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Answer:
y=2x+3
Step-by-step explanation:
Answer:
<em>60cm²</em>
Step-by-step explanation:
Length = 6cm
Breadth = 10cm
Area of rectangle = l×b
=( 10 ×6)cm
= <u>60cm²</u>
Hope it helps.
Answer:
[-4,0) ∪ [2, ∞)
Step-by-step explanation:
For piecewise function domain and range, we need to understand the difference between "(" and "[" or ")" and "]"
- The parenthesis ( "(" and ")" ) are used for "open circles" in the graph.
- The brackets ( "[" and "]" ) are use for "closed circles" in the graph.
Range is the set of y-values for which the function is defined.
Now,
The upper part of the function shows the graph going from y = 2 towards infinity (arrow). At y = 2 , there is closed circle, so this part range would be
[2, ∞) (infinity is always with parenthesis)
Now, looking at bottom part, the function is defined from 0 (open circle) to -4 (closed). so we can write:
[-4,0)
This is the range, 2nd answer choice is correct.
[-4,0) ∪ [2, ∞)