Answer:
C
Step-by-step explanation:
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
4x-13 = 2x+9 ( i think it was exterior angle property i dont remember but its true)
so, solving that eq,
4x-2x = 9+13 (grouping variables and constants)
2x=22
x=11
also, 2x+9 and 3y+2 are on a transversal, and are supplementary angles (add up to 180°)
so, solving for x in 2x+9,
2(11)+9 = 22+9 = 31°
now, 31 + 3y+2 = 180
3y = 180 - 33
y = 147/3 = 49
(hoping you understood the calculations :)
Answer:
13.41
Step-by-step explanation:
Hope it helps!
Answer:
22 cakes
Step-by-step explanation:
5 1/2kg = 11/2 = 22/4
22/4 is what you have in sugar while you only need 1/4 per cake, so you can make 22 cakes
