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Ymorist [56]
3 years ago
6

Plz help me well mark brainliest if correct......?

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

It think it is A brainliest?

Step-by-step explanation:

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√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
M
telo118 [61]

Answer:

35643

Step-by-step explanation:

M

(3x+20)

H (x+25)°

N

(x+20)

K

What is the measure of ZJHN?

25°

45°

50°

O95°

4 0
2 years ago
Simplify exspression -6 multiplied by 12 +14 -3
kompoz [17]
The answer to this question is -61
7 0
3 years ago
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O<br> Decrease 40 by ratio of 4:5
Reika [66]

A decrease in the ratio 4:5 implies that :

New quantity:Old quantity = 4:5

Let the new quantity be \bf \: x

\bf∴ x : 40 = 4:5

=  > \bf \frac{x}{40}  =  \frac{4}{5}

\bf =  > 40 \times  \frac{x}{40}  = 40 \times  \frac{4}{5}

\bf =  > x = 8 \times 4

\bf =  > x = 32

So, the new quantity is 32

4 0
3 years ago
The order in which to perform operations when simplifying an expressions with more than one operation
frosja888 [35]

Answer:

First, we solve any operations inside of parentheses or brackets. Second, we solve any exponents. Third, we solve all multiplication and division from left to right.

Step-by-step explanation:

8 0
4 years ago
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