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Ymorist [56]
3 years ago
6

Plz help me well mark brainliest if correct......?

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

It think it is A brainliest?

Step-by-step explanation:

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What is the least common denominator of the expressions?<br> x + 1/4x and 3(X + 1)/2x2​
chubhunter [2.5K]

Answer:

LCD =  4 x^2

Step-by-step explanation:

The least common denominator  : LCD

(x + 1) / 4x    and   (3(x + 1)) / 2x^2

factor  4x  :   2, 2, x

factor  2x^2 :   2, x, x^2

take highest powers  2^2 and x^2

LCD is   4*x^2

6 0
3 years ago
Need help with AP CAL
anzhelika [568]

Answer: Choice C

\displaystyle \frac{1}{2}\left(1 - \frac{1}{e^2}\right)

============================================================

Explanation:

The graph is shown below. The base of the 3D solid is the blue region. It spans from x = 0 to x = 1. It's also above the x axis, and below the curve y = e^{-x}

Think of the blue region as the floor of this weirdly shaped 3D room.

We're told that the cross sections are perpendicular to the x axis and each cross section is a square. The side length of each square is e^{-x} where 0 < x < 1

Let's compute the area of each general cross section.

\text{area} = (\text{side})^2\\\\\text{area} = (e^{-x})^2\\\\\text{area} = e^{-2x}\\\\

We'll be integrating infinitely many of these infinitely thin square slabs to find the volume of the 3D shape. Think of it like stacking concrete blocks together, except the blocks are side by side (instead of on top of each other). Or you can think of it like a row of square books of varying sizes. The books are very very thin.

This is what we want to compute

\displaystyle \int_{0}^{1}e^{-2x}dx\\\\

Apply a u-substitution

u = -2x

du/dx = -2

du = -2dx

dx = du/(-2)

dx = -0.5du

Also, don't forget to change the limits of integration

  • If x = 0, then u = -2x = -2(0) = 0
  • If x = 1, then u = -2x = -2(1) = -2

This means,

\displaystyle \int_{0}^{1}e^{-2x}dx = \int_{0}^{-2}e^{u}(-0.5du) = 0.5\int_{-2}^{0}e^{u}du\\\\\\

I used the rule that \displaystyle \int_{a}^{b}f(x)dx = -\int_{b}^{a}f(x)dx which says swapping the limits of integration will have us swap the sign out front.

--------

Furthermore,

\displaystyle 0.5\int_{-2}^{0}e^{u}du = \frac{1}{2}\left[e^u+C\right]_{-2}^{0}\\\\\\= \frac{1}{2}\left[(e^0+C)-(e^{-2}+C)\right]\\\\\\= \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

In short,

\displaystyle \int_{0}^{1}e^{-2x}dx = \frac{1}{2}\left[1 - \frac{1}{e^2}\right]

This points us to choice C as the final answer.

5 0
2 years ago
Compare the fractions 5 by 9 and 6 by 11​
alukav5142 [94]

Answer:

5/9 and 6/11

= 5/9 × 11/11 and 6/11 × 9/9

= 55/99 and 54/99

= 55/99 > 54/99

<em>therefore, 5 by 9 is greater than 6 by 11</em>

4 0
3 years ago
What is the slope of the line?<br> Helppp
Andru [333]
NO SLOPE. it doesn’t go up or dow
8 0
3 years ago
Sibal started with $500 in a bank account that does not earn interest. In the middle of every month, she withdraws 1/5 of the ac
GalinKa [24]
4/5 of the original amount at the start of the month will remain. The amount at the start of every month will change. Thus:
an = 4/5 (an-1) ; where a1 = 500.
5 0
3 years ago
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