Answer:
y = 3/5x + 62/5
Step-by-step explanation:
Equation of a line with two points is
m = y - y_1 / x - x _1
m = y_2 - y_1 / x_2 - x _1
Equating both
y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1
Using what we are provided with
(-4 , 10)(16 , -2)
x_1 = -4
y_1 = 40
x_2 = 16
y_2 = -2
Imputing the values
10 - (-2) / 16 - (-4) = y - 10 / x - (-4)
10 + 2 /16 + 4 = y - 10 / x + 4
12 / 20 = y - 10 / x + 4
Lets cross multiply
12 ( x + 4) = 20(y - 10)
Open the brackets
12x + 48 = 20y - 200
12x + 48 + 200 = 20y
12x + 248 = 20y
Following this equation of line
y = mx + C
20y = 12x + 248
Let's divide through by 20 to get y.
20y / 20 = 12x + 248 / 20
y = 12x + 248 / 20
We can separate it by
y = 12x / 20 + 248 / 20
y = 3/5x + 62/5
Therefore, the equation of the line is
y = 3/5x + 62/5
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer:
Step-by-step explanation:
Itś 5n²
It's really just knowing how to use fractions.
Say you have 8 jelly beans in a baggie. 5 are yellow and 3 are green.
What is the likelihood of pulling a green one out? Not likely.
What is the likelihood of pulling out a white one out? Impossible.
Are you getting it? Or do you need more help? :)