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3 years ago

Plz help me well mark brainliest if correct......?

Mathematics

1 answer:

Maru [420]3 years ago

4 0

Answer:

It think it is A brainliest?

Step-by-step explanation:

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√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1

Snowcat [4.5K]

$Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}$

$\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s$

7 0

3 years ago

telo118 [61]

Answer:

35643

Step-by-step explanation:

(3x+20)

H (x+25)°

(x+20)

What is the measure of ZJHN?

25°

45°

50°

O95°

4 0

2 years ago

Simplify exspression -6 multiplied by 12 +14 -3

kompoz [17]

The answer to this question is -61

7 0

3 years ago

Read 2 more answers

O<br> Decrease 40 by ratio of 4:5

Reika [66]

A decrease in the ratio 4:5 implies that :

New quantity:Old quantity = 4:5

Let the new quantity be $\bf \: x$

$\bf∴ x : 40 = 4:5$

$= > \bf \frac{x}{40} = \frac{4}{5}$

$\bf = > 40 \times \frac{x}{40} = 40 \times \frac{4}{5}$

$\bf = > x = 8 \times 4$

$\bf = > x = 32$

So, the new quantity is 32

4 0

3 years ago

The order in which to perform operations when simplifying an expressions with more than one operation

frosja888 [35]

Answer:

First, we solve any operations inside of parentheses or brackets. Second, we solve any exponents. Third, we solve all multiplication and division from left to right.

Step-by-step explanation:

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4 years ago