Well I have more than 4 but whatever....
2 x 420
3 x 280
4 x 210
5 x 168
6 x 140
7 x 120
8 x 105
10 x 84
12 x 70
14 x 60
15 x 56
20 x 24
21 x 40
24 x 35
28 x 30
2 x 2 x 210
2 x 3 x 140
2 x 5 x 84
2 x 7 x 60
3 x 5 x 56
3 x 7 x 40
5 x 7 x 24
2 x 2 x 2 x 105
2 x 2 x 3 x 70
2 x 2 x 5 x 42
2 x 2 x 7 x 30
2 x 3 x 5 x 28
2 x 3 x 7 x 20
3 x 5 x 7 x 8
2 x 2 x 2 x 3 x 35
2 x 2 x 2 x 5 x 21
2 x 2 x 2 x 7 x 15
2 x 2 x 3 x 5 x 14
2 x 2 x 3 x 7 x 10
2 x 3 x 4 x 5 x 7
<span>2 x 2 x 2 x 3 x 5 x 7</span>
Hope I Helped You!!! :-)
Have A Good Day!!!
Answer:
$50.23
Step-by-step explanation:
f(t)=1.35(t)+9.73
First I found out how many years are after 1985 so you would do 2020-1985 which equals 30.
I plug it in for t.
f(t)=1.35(30)+9.73
Then you multiply 1.35 and 30 which would leave us with.
f(t)=40.5+9.73
Add them and you get $50.23
sinx=x-x^3/3!+x^5/5!-x^7/7!+x^9/9!
sinx/3x=1/3-x^2/18+x^4/360-x^6/15120+x^8/1088640
∫sinx /3x dx=x/3-x^3/54+x^5/1800-x^7/105840+x^9/9797760
Answer:
y=2x-3
Step-by-step explanation:
I hope that helped
Answer:

Step-by-step explanation:
we know that
The exponential function is of the form

where
a is the initial value
b is the base
In this problem we have
a=200 birds
b=100%+4%=104%=104/100=1.04
substitute

Let change of variables

where
b is the amount of birds in the flock
d is the number of days since the 200 birds started