Log (x^2+3x+20)=4x you do not need to solve for x.

Mathematics

1 answer:

ruslelena [56]3 years ago

7 0

$\bf \textit{exponential form of a logarithm}\\\\
log_a b=y \implies a^y= b\qquad\qquad 
% exponential notation 2nd form
a^y= b\implies log_a b=y \\\\
-------------------------------\\\\
log_{2x}(x^2+3x+20)=4x\implies (2x)^{4x}=x^2+3x+20$

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