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Jobisdone [24]
3 years ago
12

Log (x^2+3x+20)=4x you do not need to solve for x.

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0
\bf \textit{exponential form of a logarithm}\\\\
log_a  b=y \implies   a^y=  b\qquad\qquad 
%  exponential notation 2nd form
a^y=  b\implies log_a  b=y \\\\
-------------------------------\\\\
log_{2x}(x^2+3x+20)=4x\implies (2x)^{4x}=x^2+3x+20
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This answer can also be written as

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