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zzz [600]
2 years ago
15

Need help ASAP it’s due at 12! The screen couldn’t fit, this is the clearest pic I can get! If anyone can help it will be greatl

y appreciated!

Mathematics
1 answer:
Tamiku [17]2 years ago
6 0

Step-by-step explanation:

Since ,

Money lended =$400

Intetest =27.74%

Therefore,

Intetrst=p×r×t/100,if interested monthly

=400×27.74×1/100(interested monthly)

=4×27.74

=$110.96

Interest=p×r×t/100×1/12,if interested anually

=400×27.74×1/100/12

=110.96/12

=$9.24 or it will be $110.96 if it is interested anuaaly..

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x = 18/0.75

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There are approximately 17,620 people per square mile in New York City. If New York City is 468
Simora [160]

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6 0
3 years ago
g 1) The rate of growth of a certain type of plant is described by a logistic differential equation. Botanists have estimated th
alexira [117]

Answer:

a) The expression for the height, 'H', of the plant after 't' day is;

H = \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is approximately 19.426 inches

Step-by-step explanation:

The given maximum theoretical height of the plant = 30 in.

The height of the plant at the beginning of the experiment = 5 in.

a) The logistic differential equation can be written as follows;

\dfrac{dH}{dt} = K \cdot H \cdot \left( M - {P} \right)

Using the solution for the logistic differential equation, we get;

H = \dfrac{M}{1 + A\cdot e^{-(M\cdot k) \cdot t}}

Where;

A = The condition of height at the beginning of the experiment

M = The maximum height = 30 in.

Therefore, we get;

5 = \dfrac{30}{1 + A\cdot e^{-(30\cdot k) \cdot 0}}

1 + A = \dfrac{30}{5} = 6

A = 5

When t = 20, H = 12

We get;

12 = \dfrac{30}{1 + 5\cdot e^{-(30\cdot k) \cdot 20}}

1 + 5\cdot e^{-(30\cdot k) \cdot 20} = \dfrac{30}{12} = 2.5

5\cdot e^{-(30\cdot k) \cdot 20} =  2.5 - 1 = 1.5

∴ -(30·k)·20 = ㏑(1.5)

k = ㏑(1.5)/(30 × 20) ≈ 6·7577518 × 10⁻⁴

k ≈ 6·7577518 × 10⁻⁴

Therefore, the expression for the height, 'H', of the plant after 't' day is given as follows

H = \dfrac{30}{1 + 5\cdot e^{-(30\times 6.7577518 \times 10^{-4}) \cdot t}} =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

b) The height of the plant after 30 days is given as follows

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \cdot t}}

At t = 30, we have;

H =  \dfrac{30}{1 + 5\cdot e^{-(2.02732554 \times 10^{-3}) \times 30}} \approx 19.4258866473

The height of the plant after 30 days, H ≈ 19.426 in.

3 0
3 years ago
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