Question

The product of two consecutive integers is 420 An equation is written in standard form to solve for the smaller integer by

Answer 1

The constant is zero. Hope I helped.

Answer 2

Answer:

$-420$

Explanation:

if we call the fist of the numbers $x$, then the following number is $x+1$.

the product of this two numbers according to the problem is:

$(x)(x+1)=420$

which results in:

$x^2+x=420$

The standar form of a quadratic equation is

$Ax^2+Bx+C=0$

so we must make the equation equal to zero: $x^2+x-420=0$

and this way we can see that the constant $C$ in the quadratic expression is $-420$.

if you want the values of the consecutive numbers, they are 20 and 21.