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Trava [24]
3 years ago
13

The light-gathering capacity of a telescope is dependent upon the: magnification focal length size of human iris area of apertur

e
Physics
2 answers:
lilavasa [31]3 years ago
8 0
<span>Well, light gathering capacity of a telescope is dependent upon the area of aperture</span>
gayaneshka [121]3 years ago
4 0

<u>Answer: </u>The correct answer is area of aperture.

<u>Explanation:</u>

Telescope is an optical instrument which focuses light towards one point and makes far away things look nearer. It is made up of the arrangement of lenses or curved mirrors and lenses which focuses the light and makes the image of the object magnified.

The light-gathering capacity of a telescope is the ability to resolve small detail depends on the diameter of its objective lens. Larger the area of aperture, telescope can collect more light ans as a result, fine detail is obtained.

Hence, the correct answer is area of aperture.

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A 1200-kg car initially at rest undergoes constant acceleration for 9.4 s, reaching a speed of 11 m/s. It then collides with a s
Natalka [10]

To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,

KE_i = KE_f

KE_f = \frac{1}{2} mv^2

Here,

m = Mass

V = Velocity

Replacing,

KE_f = \frac{1}{2} (12000)(11)^2

KE_f = 72600J

Therefore the  final kinetic energy of the two car system is 72.6kJ

8 0
4 years ago
A point P1 is located by the vector A = (3.74)î + (1.64)ĵ and a point P2 is located by the vector B = (1.60)î + (3.66)ĵ. The vec
seropon [69]

Answer:

\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )

Explanation:

The vector that point from point P1 to point P2 its found simply by taking the vector at which point P2 its located and subtracting the vector at which point P1 its located:

\vec{C} = \vec{B} - \vec{A}

So:

\vec{C} = ( \ 1.60 \ , \ 3.66 \ ) - ( \ 3.74 \ , \ 1.64 \ )

\vec{C} = ( \ 1.60 \ - \ 3.74 \ , \ 3.66 \ - \ 1.64 \ )

\vec{C} = ( \ - 2.14 \ , \ 2.02 \ )

4 0
3 years ago
To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3
iren [92.7K]

Answer:

372.3 J/^{\circ}C

Explanation:

First of all, we need to calculate the total energy supplied to the calorimeter.

We know that:

V = 3.6 V is the voltage applied

I = 2.6 A is the current

So, the power delivered is

P=VI=(3.6)(2.6)=9.36 W

Then, this power is delivered for a time of

t = 350 s

Therefore, the energy supplied is

E=Pt=(9.36)(350)=3276 J

Finally, the change in temperature of an object is related to the energy supplied by

E=C\Delta T

where in this problem:

E = 3276 J is the energy supplied

C is the heat capacity of the object

\Delta T =29.1^{\circ}-20.3^{\circ}=8.8^{\circ}C is the change in temperature

Solving for C, we find:

C=\frac{E}{\Delta T}=\frac{3276}{8.8}=372.3 J/^{\circ}C

5 0
3 years ago
Physical activity is the most important thing you can do to improve and maintain health-related physical fitness. Which list con
katovenus [111]

Answer:

I guess it's d because age environment heredity Nd maturation r more obvious factors if we compre with only physical fitness

8 0
3 years ago
A book on a 2-meter high shelf has a mass of 0.4 kg. What is its potential energy?
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Answer:

how can we get the best out with a little of my life and I think the most common reason I would n I have been having this problem for years is done in my life as the other people

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