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3241004551 [841]

2 years ago

15

Freida stands on a hill with a slope of 12 degrees. If her mass is 65 kg, what is the magnitude of the normal force acting on he

r?
A. 623 N
B. 637 N
C. 132 N
D. 601 N

2 answers:

aliina [53]2 years ago

7 0

Answer:

b

Explanation:

Svetradugi [14.3K]2 years ago

7 0

Answer:

b

Explanation:

I did my math and made sur got it correct

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5. A ball is sitting at rest on the floor. What will happen if a balanced force is applied to the ball? *

Leno4ka [110]

When the balanced force is applied on the ball It will roll away from the force.

<u>Explanation:</u>

A ball lies on the floor in rest. If the balanced force is applied to

the ball, the force will push away.

The forces would include gravity and the forces of air particles entering the ball from almost all directions.
And the ground is exercising the force and shifting away from the impact.

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3 0

3 years ago

As a quality test of ball bearings, you drop bearings (small metal balls), with zero initial velocity, from a height of 1.94 m i

11Alexandr11 [23.1K]

Answer:

The average acceleration of the bearings is $0.77\times10^{3}\ m/s^2$

Explanation:

Given that,

Height = 1.94 m

Bounced height = 1.48 m

Time interval $t=14.86\times10^{-3}\ s$

Velocity of the ball bearing just before hitting the steel plate

We need to calculate the velocity

Using conservation of energy

$mgh=\dfrac{1}{2}mv^2$

Put the value into the formula

$9.8\times1.94=\dfrac{1}{2}\times v^2$

$v=\sqrt{2\times9.8\times1.94}$

$v=6.166\ m/s$

Negative as it is directed downwards

After bounce back,

We need to calculate the velocity

Using conservation of energy

$mgh=\dfrac{1}{2}mv^2'$

Put the value into the formula

$9.8\times1.48=\dfrac{1}{2}\times v^2'$

$v'=\sqrt{2\times9.8\times1.48}$

$v'=5.38\ m/s$

We need to calculate the average acceleration of the bearings while they are in contact with the plate

Using formula of acceleration

$a=\dfrac{v-v'}{t}$

Put the value into the formula

$a=\dfrac{5.38-(-6.166)}{14.86\times10^{-3}}$

$a=776.98\ m/s^2$

$a=0.77\times10^{3}\ m/s^2$

Hence,The average acceleration of the bearings is $0.77\times10^{3}\ m/s^2$

6 0

3 years ago

What are the uses of rockets

lora16 [44]

They are used to be able to go out of Earth and into space to Be able to explore and toBe able to prove and tell about Earth and space

8 0

3 years ago

Sitting in a chairlift, Rebecca has a gravitational potential energy of 5,997.6

stira [4]

Answer:

B) 12 m

Explanation:

Gravitational potential energy is:

PE = mgh

Given PE = 5997.6 J, and m = 51 kg:

5997.6 J = (51 kg) (9.8 m/s²) h

h = 12 m

8 0

3 years ago

Definition of force equation

Georgia [21]

Answer:

force is that push or pull of the body that change or tends to change the state of rest or uniform motion in a straight line.

Explanation:

hope it is helpful to u

8 0

2 years ago