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creativ13 [48]
1 year ago
14

a spring is stretched 20 cm by a 30.0 n force. determine the work done in stretching the spring from 0 to 40 cm?

Physics
1 answer:
Alekssandra [29.7K]1 year ago
3 0

The work done when a spring is stretched from 0 to 40cm is 4J.

What is work done?

Work done is the magnitude of force multiplied by displacement of an object. It is also the amount of energy transferred to an object when work is done on that.

The work done on the spring to stretch to 40cm is,

F = kx

where F is force, k is force constant.

k = F / x = 10 N / 20 * 10^-2 m = 50 N/m

W = 0.5 * k * (x)^2

where W = work done, k = force constant.

W = 0.5 x 50 x (40 x 10^-2)^2 = 4 J.

Therefore, the work done on the spring when it is stretched to 40cm is 4J.

To learn more about work done click on the given link brainly.com/question/25573309

#SPJ4

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A transformer has 1500 turns on the primary coil and 30 000 turns on the secondary coil. What is the potential difference across
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turle

Explanation:

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3 years ago
You are driving your 1700 kg car at 21 m/s down a hill with a 5.0∘ slope when a deer suddenly jumps out onto the roadway. You sl
podryga [215]

Answer:

d = 27.7 m

Explanation:

Here the car is driving on the inclined plane

So here we can say that work done by the gravity and work done by friction is equal to change in kinetic energy of the system

So here we can write it as

mgsin\theta \times d - F_f \times d = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 1700 kg

v_f = 0

v_i = 21 m/s

F_f = 1.5 \times 10^4 N

(1700)(9.81)sin5 (d) - (1.5\times 10^4)d = 0 - \frac{1}{2}(1700)(21^2)

1453.5 d - (1.5\times 10^4)d = -374850

d = 27.7 m

6 0
3 years ago
Dentists use special lamps that consist of a concave mirror and a small, bright light source that is fixed on the principal axis
Stella [2.4K]

Answer: 140cm

Explanation:

Radius of curvature r = 2f

Where f is the focal point

f = 70cm, therefore

r =2 x 70 = 140cm

7 0
3 years ago
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In the periodic table, the properties repeat in what direction?​
pogonyaev

Answer:

Left to right and top to bottom

Explanation:

On the periodic table, the properties repeat from left to right and from top to bottom.

Periodic properties have a pattern from the top to the bottom or down a group or family.

Also, across the period from left to right, they also show a repeating pattern.

  1. Certain properties increase from left to right and decreases from top to bottom. E.g. electronegativity.
  2. Also, some properties decreases from left to right and increases from top to bottom e.g. atomic radius.
7 0
4 years ago
A copper rod has a length of 1.7 m and a cross-sectional area of 3.6 10-4 m2. One end of the rod is in contact with boiling wate
Lina20 [59]

Answer:

Mass of ice per second melt is 2.74×10^-5Kg/s

Explanation:

Temperature of one end of the copper rod is 100°C boiling point of water and the other end of the rod is 0°C

Temperature difference in the copper rod = 100 - 0 = 100°C

Cross sectional area = 3.6×10^-4m^2

Length of rod , L = 1.7m

Amount of heat transfer from the boiling water to the ice water mix through the copper rod is given by:

Q = KA◇T/ L

Q = (390×(3.6×10^-4)×100°C)/1.7

Q = 14.04/1.7

Q = 8.26J/s

From the equation

Q = mLf

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Where Lf = Latent heat of fusion for water= 3.34×10^5J/Kg

m = 8.26/(3.34×10^5)

m = 2.74×10^-5Kg/s

3 0
3 years ago
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