1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
GrogVix [38]
3 years ago
9

A quantity of a gas has an absolute pressure of 400 kPa and an absolute temperature of 110 degrees kelvin. When the temperature

of the gas is raised to 235 degrees kelvin, what is the new pressure of the gas? (Assume that there's no change in volume.)
a. 3.636 kPa
b. 854.46 kPa
c. 1.702 kPa
d. 510 kPa
Physics
1 answer:
shepuryov [24]3 years ago
4 0

You can make sure there's no change in volume by keeping
your gas in a sealed jar with no leaks.  Then you can play with
the temperature and the pressure all you want, and you'll know
that the volume is constant.

For 'ideal' gases,

       (pressure) times (volume) is proportional to (temperature).

And if volume is constant, then

                 (pressure) is proportional to (temperature) .

So if you increase the temperature from 110K to 235K,
the pressure increases to  (235/110)  of where it started.

     (400 kPa) x (235/110)  =  854.55 kPa. (rounded)

Obviously, choice-b is the right one, but
I don't know where the .46 came from.
 
You might be interested in
HELP I DONT HAVE MUCH TIME ILL time BRAINLIEST 10poINTSSSSSS HURYYYY
Soloha48 [4]
1.the sun must be lined up with the moon and earth all must be aligned for this to happen
6 0
2 years ago
Read 2 more answers
A 0.59 kg bullfrog is sitting at rest on a level log. how large is the normal force of the log on the bullfrog?
ladessa [460]
<span>The bullfrog is sitting at rest on the log. The force of gravity pulls down on the bullfrog. We can find the weight of the bullfrog due to the force of gravity. weight = mg = (0.59 kg) x (9.80 m/s^2) weight = 5.782 N The bullfrog is pressing down on the log with a force of 5.782 newtons. Newton's third law tells us that the log must be pushing up on the bullfrog with a force of the same magnitude. Therefore, the normal force of the log on the bullfrog is 5.782 N</span>
7 0
3 years ago
Which statement describes why scientific notation is useful? It makes very small numbers into whole numbers. It converts fractio
disa [49]

It makes calculations with very large and small numbers easier.

Scientific notation is a system used in order to It makes calculations with very large and small numbers easier. It is useful as it allows very large number that would take a lot of space to write otherwise, and it allows them to be calculated easier. 10^{23} for example is a incredible large number, but written in this form is immediately understandable and useful for calculation.

3 0
3 years ago
Read 2 more answers
A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber
Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}

Now calculate the bouyant force acting on the lead

F_L = Vpg

F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N

This force will act in upward direction

Gravitational force on the lead due to its mass  will act in downward direction

Hence the difference of this two force

T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N

If V is the volume submerged in the water then bouyant force on the bobber is

F_B=V'pg

Equate bouyant force with the tension and gravitational force

F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}

Now Total volume of bobble is

\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\

=\large\boxed{4.52 \%}

7 0
3 years ago
In which one of the following situations does a car have a WESTWARD acceleration? The car travels westward and slows down. The c
DENIUS [597]

Explanation:

Let east direction is negative and west direction is positive. The acceleration of an object is given by :

a=\dfrac{v-u}{t}

Where

v is the final speed

u is the initial speed

t is the time taken

As the car decelerates, the final speed of the car is less as compared to the initial speed. As a result, its acceleration is negative. It means the car travels eastward and slows down. Hence, this is the required solution.

4 0
3 years ago
Other questions:
  • What occurs when an object travels in a curved path
    13·2 answers
  • When a potassium atom forms an ion, it loses one electron. What is the electrical charge of the potassium ion?
    12·2 answers
  • A string is attached to the rear-view mirror of a car. A ball is hanging at the other end of the string. The car is driving arou
    6·1 answer
  • Pallu
    15·2 answers
  • A ball rolls across the floor at a constant speed, what will happen to it if there is no friction?
    12·1 answer
  • What is Ethyl butyrate used for
    7·1 answer
  • suppose you were pushing on a heavy bucket of stones it 100 N of force, and it did not move. How many newtons of force would be
    10·1 answer
  • In the laboratory you will find three bottles with the following labels:
    12·1 answer
  • Omar rubs a balloon with wool, giving the balloon a
    7·1 answer
  • Might it be possible to explain the interaction of the rod and pieces of paper as a gravitational interaction? please explain wh
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!