Question

Consider the function represented by the equation 1/2 J + 1/4 k equals 3 which shows the equation written in function notation with K as the independent variable

Answer 1

we have

$\frac{1}{2} J+\frac{1}{4} K=3$

Step 1

Solve for J

$\frac{1}{2} J+\frac{1}{4} K=3$

Multiply by $2$ both sides

$2*\frac{1}{2} J+2*\frac{1}{4} K=2*3$

$J+\frac{1}{2} K=6$

Subtract $\frac{1}{2} K$ both sides

$J+\frac{1}{2} K-\frac{1}{2} K=6-\frac{1}{2} K$

$J=6-\frac{1}{2} K$

Step 2

Convert the equation in function notation

Let

$f(k)=J$

$f(k)=6-\frac{1}{2} K$

$f(k)=-\frac{1}{2} K+6$

therefore

the answer is

$f(k)=-\frac{1}{2} K+6$

Answer 2

F(k) = -1/2k + 6

You can get this by solving for J and then using f(k) in its place.