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Phantasy [73]
3 years ago
9

Please help i'll give you brainliest answer!

Mathematics
1 answer:
cupoosta [38]3 years ago
6 0

Answer:

1. B. 5.76 × 10¹⁴ miles.

2. D. $15,494.70

Step-by-step explanation:

Question 1: We have,

Distance light traveled in one year = 5.88 × 10¹² miles.

Since, the star is 9.8 × 10¹ light years away.

So, we get,

Total number of miles the star is away = 5.88 × 10¹² × 9.8 × 10¹ = 57.62 × 10¹³ miles.

Hence, the total number of miles are 5.76 × 10¹⁴ miles.

Question 2: We have,

Principle amount, P= $1,600

Rate of interest, r = 7% = 0.07

Time period, t = 33 years

Moreover, the interest is compounded twice per year i.e. n=2.

Since, Amount = P(1+\frac{r}{n})^{nt}

i.e. Amount = 1600(1+\frac{0.07}{2})^{2\times 33}

i.e. Amount = 1600(1+\frac{0.035)^{66}

i.e. Amount = 1600(1.035)^{66}

i.e. Amount = 1600\times 9.68418}

i.e. Amount = $15,494.70

Hence, the balance in the account is $15,494.70.

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In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour
Lesechka [4]

Answer:

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=54 represent the sample mean  

\mu population mean (variable of interest)

\sigma=21 represent the sample standard deviation

n=16 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=1-0.9=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

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