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DaniilM [7]
3 years ago
12

Identify the number of possible outcomes when the spinner is spun? PLEASE ANSWER FAST!!

Mathematics
1 answer:
Arturiano [62]3 years ago
4 0

Answer:

there are 6 outcomes

Step-by-step explanation:

there are only 6 spots, therefore it has to be 6

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I have this question and I need it done bad... Help please? Picture included I was never taught matrix
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Multiply the numbers on the major axis which are 2 and -9 to get -18.  Subtract from that 3*4 = 12.  So -18-12 = -30.  That's the determinant.
6 0
4 years ago
Solve for x: −4x+6(6−2x)=−7x−36
ValentinkaMS [17]

Answer:

x = 8

Step-by-step explanation:

-4x + 6(6 - 2x) = -7x - 36

-4x + 36 - 12x = -7x - 36

-16x + 36 = -7x - 36

<u>       +36           +36</u>

-16x + 72 = -7x

<u>+16x           +16x</u>

72 = 9x

divide by 9

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4 0
3 years ago
Read 2 more answers
write the equation that describes the line in slope-intercept form. slope = 4, point (3, −2) is on the line y = 4x 14 y = 4x − 2
amid [387]
Equation of a line is given by y - y1 = m(x - x1) where m is the slope and (x1, y1) is any point on the line.

y - (-2) = 4(x - 3)
y + 2 = 4x - 12
y = 4x - 12 - 2
y = 4x - 14
5 0
3 years ago
weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of $50. find the probabi
kenny6666 [7]

Answer:

0.34134

Step-by-step explanation:

In other to solve for this question, we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = Standard deviation

We are told in the question to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

From tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

Then, the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

Hence, The probability that a worker selected at random makes between $350 and $400 = 0.34134

7 0
4 years ago
The center of a hyperbola is (−4,3) , and one vertex is (−4,7) . The slope of one of the asymptotes is 2.
Monica [59]

Answer:

The answer to your question is below

Step-by-step explanation:

C (-4, 3)

V (-4, 7)

asymptotes = 2 = \frac{b}{a}

- This is a vertical hyperbola, the equation is

       \frac{(y - k)^{2} }{a^{2} } + \frac{(x - h)^{2} }{b^{2} } = 1

slope = 2

a is the distance from the center to the vertex = 4

b = 2(4) = 8

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       \frac{(y - 3)^{2} }{16} + \frac{(x + 4)^{2} }{64} = 1

7 0
3 years ago
Read 2 more answers
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