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lozanna [386]
2 years ago
9

Explain why the graph has values for years that are still in the future​

Mathematics
1 answer:
Ivanshal [37]2 years ago
5 0

Answer:

Consider combining several bar graphs into one large bar graph with a different colors for each time period. By combining bar graphs in this manner, you can more readily see trends for different times periods and notice deviations, which is helpful in making predictions

Step-by-step explanation:

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Please help me ASAP im struggling :(
erik [133]

Answer:

The answer is C!!

Step-by-step explanation:

7 0
2 years ago
IF YOU HELP ME ILL WILL GIVE YOU BRAINLIST AND 50 PONITS HELP ME PLZZZZZ
labwork [276]
I think the answer is A because the data is skewed to the right 
The median (middle) isn't 10, it's 8 
The interquartile range (IQR) is 7 not 6 because you have to subtract the first and third quartile 13 - 6 = 7 not 6

Hope this helps! ;)
8 0
3 years ago
Read 2 more answers
Fill in the blanks with the correct symbol to make each statement true. Use +,-, x, divide or parentheses to obtain the given so
Stolb23 [73]

Answer:

4×4÷4+4=4

(4×4+4)÷4=5

4+4-4÷4=7

5 0
3 years ago
For what value of c does x^2−2x−c=4 have exactly one real solution?<br> PLEASE HELP!!!!!!!
Paul [167]

Answer:

-5

Step-by-step explanation:

Moving all terms of the quadratic to one side, we have

x^2-2x-(c+4)=0.

A quadratic has one real solution when the discriminant is equal to 0. In a quadratic ax^2+bx+d, the discriminant is \sqrt{b^2-4ad}.

(The discriminant is more commonly known as \sqrt{b^2-4ac}, but I changed the variable since we already have a c in the quadratic given.)

In the quadratic above, we have a=1, b=-2, and d=-(c+4). Plugging this into the formula for the discriminant, we have

\sqrt{(-2)^2-4(1)(-(c+4)).

Using the distributive property to expand and simplifying, the expression becomes

\sqrt{4-4(-c-4)}=\sqrt{4+4c+16}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{20+4c}\\~~~~~~~~~~~~~~~~~~~~~~=\sqrt{4}\cdot\sqrt{5+c}\\~~~~~~~~~~~~~~~~~~~~~~=2\sqrt{c+5}.

Setting the discriminant equal to 0 gives

2\sqrt{c+5}=0.

We can then solve the equation as usual: first, divide by 2 on both sides:

\sqrt{c+5}=0.

Squaring both sides gives

c+5=0,

and subtracting 5 from both sides, we have

\boxed{c=-5}.

3 0
2 years ago
N(x)=2x+7;(x)=17, what is the value of x so that the function has a given value
miskamm [114]
2(17)+7

34+7

N(17)=41

Brainliest?
5 0
3 years ago
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