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3 years ago

12

Find the product. Enter the product in simplest form. 11/12 x 5 PLZ HELP MEEEEEEEE

1 answer:

tester [92]3 years ago

3 0

Answer:4 7/12

Step-by-step explanation:

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Casi drove 135 miles in 3 hours. Use a proportion to find how long it would take her to drive 360 miles at the same speed.

galina1969 [7]

Answer:

8 hours

Step-by-step explanation:

We are given that

Casi traveled distance in 3 hours=135 miles

We have to find the time taken by Casi to drive 360 miles at the same speed using proportion .

Let time taken by Casi to drive 360 miles=x

We know that

Speed= $\frac{Distance}{time}$

Using proportion

$\frac{a}{b}=\frac{c}{d}$

$\frac{135}{3}=\frac{36}{x}$

$x=\frac{360\times 3}{135}$

$x=8$

Hence, the time taken by Casi to drive 360 miles=8 hours

8 0

3 years ago

Originally priced at $19.59, a video game was found on a 62% off rack. What is the sale price of the video game?

Brilliant_brown [7]

$7.44

Hope I helped!!
giving me brainliest is much appreciated.. =)

6 0

3 years ago

Please help me I want to go play outside with my sisters

FinnZ [79.3K]

Answer:

51

Step-by-step explanation:

4 0

3 years ago

A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

4 years ago

Identify the domain and range of each relationship. Represent the relation with a mapping diagram. Is the relation a function?

Ivenika [448]

Remember, to be a function, all elements in the domain should correspond to one element in the range.
The domain is the x coordinate, range is the y coordinate.
The domain we can solve for as the set {4.2, 5, 7}. The range is the set {0, 1.5, 2.2, 4.8}.
But we see that an element in the domain corresponds to more than one element in the range, thus making it not a function.

4 0

4 years ago