Answer:
About 5.5, but it is technically closer to 5.6 so I am not entirely sure
Step-by-step explanation:
Since EB and DC are parallel, triangles ABE and ACD are similar by AA. Therefore:
Hope this helps!
The answer to this is
3(x+1)(x+8)
Answer:
(look below)
Step-by-step explanation:
i used to do ixl so heres an appropriate answer:
1 21
3 63
5 105
7 147
:3
Answer:
4.8m
Step-by-step explanation:
Answer: A. "Segment AD bisects angle CAB." is the right answer.
Step-by-step explanation:
Given : In ΔABC ,AC≅AB.
⇒∠ACB=∠CBA....(1) (∵ angles opposite to equal sides of a triangle are equal )
Now in ΔACD and ΔABD
AD=AD (common)....(2)
Here we need one more statement to prove the triangles congruent that is only statement (A) fits in it.
If AD bisects ∠CAB then ∠CAD=∠BAD..(3)
Now again Now in ΔACD and ΔABD
∠ACB=∠CBA [from (1)]
AD=AD [common]
∠CAD=∠BAD [from (3)]
So by ASA congruency criteria ΔADC≅ΔABD.
