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jasenka [17]
3 years ago
12

What is the probability of picking an orange marble and flipping tails? ​ 1/7 1/14 2/14 8/14

Mathematics
2 answers:
vladimir2022 [97]3 years ago
4 0

Answer:

Flipping tails would be 1/2 but how many marbles are there and how many orange ones are there?

Step-by-step explanation:

xenn [34]3 years ago
4 0

Answer:1/14 chance

Step-by-step explanation: Hope this helps <3

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SUPER EASY WILL GIVE BRAINLEIST IF DONE BEFORE 10 PM PLS HURRY. IF U HAVE TIME PLS HELP ME ON OTHER QUESTIONS THANK YOU &lt;3
Murljashka [212]
Tell me if you have any questions or you need a step by step explanation

8 0
3 years ago
How and what is the answer
lana [24]
C ) 131 is the answer

in the upside-vertex (not inverted) triangle, angle to your left hand side would be equal to x (as interior alternate angles) = 68

and the angle to the right would be 180-y= 180-117 = 163 (as linear angles)

so the angle at the vertex = 180 - (68 + 163) =49  (as angles in a triangle sum upto 180)

so the angle mz = 180 - 49 = 131 degrees (as linear pair of angles or angle in a straight line)
4 0
4 years ago
The perimeter of the rectangle below is 65 inches.
Tems11 [23]

Answer:

A :-) Given -

perimeter = 65 inches

Side ‘a’ = 2x

Side ‘b’ = 3 1 by 4x + 1

Solution -

Perimeter = 65

= a + b = 65

= 2x + 3 1 by 4x + 1 = 65

( 3 1 by 4 = 4 x 3 + 1 = 12 + 1 by 4

= 13 by 4 )

= 2x + 13 by 4x + 1 = 65

= 2x + 13 by 4x = 65 - 1

= 2x + 13 by 4x = 64

= 15 by 4 x = 64

= x = 64 x 4 by 15

= x = 256 by 15

= x = 17.06

.:. The value of x = 17.06.

7 0
3 years ago
Vector question, please help​
77julia77 [94]

Answer:

yes.

Step-by-step explanation:

3 0
3 years ago
. Given that O is the centre of the following circle, find the values of the unknowns.​
alex41 [277]

Given:

Radius of circle is 13 cm

Height of triangle is 5 cm

To find:

Value of 'a' and 'b'

Steps:

To find value of 'a', we will use Pythagoras theorem as the triangle is a right angle triangle,

A² + B² = C²

a^{2} + 5^{2} = 13^{2}

a^{2} + 25 = 169

a^{2} = 169 - 25

a^{2} = 144

\sqrt{a^{2}}=\sqrt{144}

a = 12

Now to find the value of 'b', i will use law of cosine,

c=\sqrt{a^{2}+b^{2}-2ab(cos\beta ) }

12 = \sqrt{13^{2}+5^{2}-2(5)(13)(cos\beta )}\\12=\sqrt{169 + 25-130(cos\beta )}\\12=\sqrt{194-130(cos\beta )}\\144 = 194 - 130(cos\beta )\\50 = 130(cos\beta )\\cos\beta =   0.3846\\\beta  = cos^{-1}(0.3846)\\\beta = 67.38

Therefore, the values of 'a' and 'b' is 12 and 67.38 respectively

Happy to help :)

If u need any help feel free to ask

3 0
3 years ago
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