1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga2289 [7]
4 years ago
11

What is 2 times 2 and 7/8

Mathematics
2 answers:
astraxan [27]4 years ago
8 0
2 times 2 equals 4
then you do 4/1*7/8 that makes 4*7=28
and 8*1=8 so it's 28/8 and we reduce that to the fraction 28/8 is equivalent to      =3 1/2.
anyanavicka [17]4 years ago
6 0
2 x 2 7/8 = 5 3/4 hope it helps

You might be interested in
What is my number my number is a perfect square the only prime number in it prime factorization is 2 my number is a factor of 32
WITCHER [35]
Nmkndj;n;bnjngfndjknh;rtnh 216g6n
543646245mh.nrkjhgjn.kjgnrjkbuhjtbyultkngu;njktnj totm,my fotrtunanhioubgrviuebglryrhntonm my forytunabjvfdjkfvghyulbfwqlcbherovbegiunj gtjgbasyhj.bsf.fjkbgilhbjbhfljbvhuj
4 0
3 years ago
A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular
Oksi-84 [34.3K]

Answer:

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

Step-by-step explanation:

we know that

we can divide the regular hexagon into 6 identical equilateral triangles

see the attached figure to better understand the problem

The approximate area of the circle is approximately the area of the six equilateral triangles

Remember that

In an equilateral triangle the interior measurement of each angle is 60 degrees

We take one triangle OAB, with O as the centre of the hexagon or circle, and AB as one side of the regular hexagon

Let

M  ----> the mid-point of AB

OM ----> the perpendicular bisector of AB

x ----> the measure of angle AOM

m\angle AOM =30^o

In the right triangle OAM

tan(30^o)=\frac{(a/2)}{r}=\frac{a}{2r}\\\\tan(30^o)=\frac{\sqrt{3}}{3}

so

\frac{a}{2r}=\frac{\sqrt{3}}{3}

we have

r=3\ units

substitute

\frac{a}{2(3)}=\frac{\sqrt{3}}{3}\\\\a=2\sqrt{3}\ units

Find the area of six equilateral triangles

A=6[\frac{1}{2}(r)(a)]

simplify

A=3(r)(a)

we have

r=3\ units\\a=2\sqrt{3}\ units

substitute

A=3(3)(2\sqrt{3})\\A=18\sqrt{3}\ units^2

Therefore

The approximate are of the inscribed disk using the regular hexagon is A=18\sqrt{3}\ units^2

6 0
3 years ago
Can someone answer this for me?
Ksju [112]

Answer:

whats the question?

Step-by-step explanation:

8 0
3 years ago
n the expression 5x6 + 3xy − 7yz2 + , which of the following choices is the exponent in the term 5x6?
astra-53 [7]

Answer:

7yz2+

Step-by-step explanation:

3 0
4 years ago
What is 1 fifth of a clock?
Whitepunk [10]
2.4 hours or 2 hours and 24 minutes represents \frac{1}{5} of a clock. 

The easiest way to find this is to divide 12 by 5 since there are twelve hours on a clock. 
I got the 24 minutes by multiplying 60(minutes there are in an hour) by .4 and got 24.
6 0
3 years ago
Read 2 more answers
Other questions:
  • Increased movement of the particles in a solid comes from increased ________.
    15·1 answer
  • Which statement about the product of 7/10 and 7/8 is true
    13·1 answer
  • Pls help me solve this problem!!
    10·1 answer
  • X = y + 3 <br> 2 x - y = 5
    9·1 answer
  • Helpp me plzz!!! haha
    8·1 answer
  • Rewrite each number from standard notation to scientific notation. 18,200,000,000
    10·1 answer
  • kevin used a 50 dollar bill to pay 4 shirts the cashier give kevin 6.44 of change how much did kevin spend on the shirts
    9·1 answer
  • Jenna and her mom are addressing envelopes for Jenna's wedding invitations. So far, Jenna has addressed 2/9 of the envelopes, an
    5·2 answers
  • Which solid has a greater volume? O A. Figure A 48 B. Figure B O C. they are equal A 2 O D. need more information​
    10·1 answer
  • Please help!! giving brainlest , please be serious. due in a few minutes thanks!
    15·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!