Considering that the square root of 9 is of 81 and of 10 is of 100, we have that the expression that has a value between 9 and 10 is given by:
B.) √89
E.) ![\sqrt[3]{750}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B750%7D)
F.) ![\sqrt[3]{999}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B999%7D)
<h3>How the square root of a number is used to solve this question?</h3>
We suppose numbers n and m, with square roots given, respectively, by n² and m².
Then, the square roots of all numbers between n² and m² have values between n and m.
In this problem, the square roots are given by:
Hence, the square root of all values between 82 and 99 are values between 9 and 10, thus option B is correct.
As for the cubic root, we apply the same logic and have that:
Hence options E and F are also correct, as the values between 730 and 999 have cubic roots between 9 and 10.
More can be learned about the value of a expression at brainly.com/question/25537936
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So, you had done everything right so far (other than squaring the 2), but that was only half of the question.
to find the least common multiple, you need to first figure out what the prime factors have in common.
each have two twos. both have one 5, so we know our answer will look something like
now to figure out the other stuff... we have to represent the greatest amount of everything that is left, and we have 3s and 7s left over, so we need to figure out how many of each we need.
one has one 3 and one has two, so we need two threes. now our equation is
what's the only number we have to deal with? 7...
how many sevens does 60 have? 0, and 630 has 1, so we know we need one 7. our answer becomes
Answer:
Area of the triangle =(height x base ) /2
A=(17x12)/2
A=102
the area of the triangle is 102
Answer:
C
Step-by-step explanation:
This is actually a combination problem as we are trying to select groups of 5 from the 15 qualified trainees.
To do this, we use the combinatorial approach. This is done by using the formula 15C3 = 15!/(15-3)!3!
This gives a value of 455
Answer:
A
Step-by-step explanation:
When an expression is reflected across the x-axis, the x values stay the same but the y values are now negative.
