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alex41 [277]
3 years ago
11

Help im not sure if i am doign this right or not

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
3 0

Answer:

(a) <em>X</em> = {Bilk, Jas, Piaf, Sydow, Wil}

(b) <em>Y</em> = {Jas, Sydow, Tixo}

Hope that helps.

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Which formula should be used to calculate the amount of paper needed?
bogdanovich [222]

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Step-by-step explanation:

I=PRT where I =interest P=principal, R=rate, and T =time is

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A bank sampled its customers to determine the proportion of customers who use their debit card at least once each month. A sampl
Zinaida [17]

Answer:

(0.084,0.396)

Step-by-step explanation:

The 99% confidence interval for the proportion of customers who use debit card monthly can be constructed as

p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

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p=0.24

q=1-p=1-0.24=0.76

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p-z_{\frac{\alpha }{2}} \sqrt{\frac{pq}{n} }

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0.24-2.58(0.0604)

0.24-0.155832

By rounding to three decimal places we get,

0.084

The 99% confidence interval for the proportion of customers who use debit card monthly is (0.084,0.396).

3 0
3 years ago
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is a
Lyrx [107]

Answer:

A) 0

Step-by-step explanation:

When x is divided by 11, we have a quotient of y and a remainder of 3

x/11 = y + 3

x = 11y + 3 ........(1)

When x is divided by 19, we have a remainder of 3 also

x/19 = p + 3 (p = quotient)

x = 19p + 3 ..........(2)

Equate (1) and (2)

x = 11y + 3 = 19p + 3

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11y = 19p + 3 -3

11y = 19p

Divide both sides by 11

11y/11 = 19p/11

y = 19p/11

y and p are integers. 19 is a prime number. P/11 is also an integer

y = 19(integer)

This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0

8 0
3 years ago
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