Answer:
The distance cover by teacher in 30 minutes is 4
miles .
Step-by-step explanation:
Given as :
The distance cover by student = d = 3
miles
i.e d =
miles
The time taken by student to cover
miles distance = t = 30 minutes
Let The speed of student = s miles per minute
∵ Speed = ![\dfrac{\textrm Disatnce}{\textrm Time}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Ctextrm%20Disatnce%7D%7B%5Ctextrm%20Time%7D)
Or, s = ![\dfrac{d}{t}](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bt%7D)
Or, s = ![\frac{\frac{10}{3}}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B10%7D%7B3%7D%7D%7B30%7D)
i.e s = 0.111 miles per min
So, The speed of student = s = 0.111 miles per min
<u>Now, Again</u>
The speed of teacher = 1
times as fast as student
Let The speed of teacher = S miles per min
∵ The speed of teacher =
× speed of student
So, S =
× s
Or, S =
× 0.111 miles per min
Or, S =
mil/min
i.e, S = 0.13875 miles per min
So, The speed of teacher = S = 0.13875 miles per min
Let The distance cover by teacher = D miles
The time taken by teacher to cover D miles distance = T = 30 minutes
∵ Distance = Speed × Time
Or, D = S × T
Or, D = 0.13875 miles per min × 30 min
∴ D = 4.1625 miles
i.e D = 4
miles
So, The distance cover by teacher in 30 minutes = D = 4
miles
Hence,The distance cover by teacher in 30 minutes is 4
miles . Answer