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inn [45]
3 years ago
14

Sooooooo what While scuba diving, Rajeev dove to a depth of 12.6 feet below the surface of the water and then descended another

8.7 feet. What expression can be used to find Rajeev’s new position?
12.6 – 8.7
–12.6 – 8.7
–12.6 – (–8.7)
12.6 – (–8.7)
and hi austin <3
Mathematics
1 answer:
Dmitry [639]3 years ago
5 0
The second one “-12.6 - 8.7”
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Step-by-step explanation:

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Q(x)=x^3+ax^2+2b is divided by (x-3) and has a remainder of 4. Find the values of "a" and "b"​
Sati [7]

Answer:

Let p(x) = x3 + ax2 + bx +6

(x-2) is a factor of the polynomial x3 + ax2 + b x +6

p(2) = 0                                                                                      

p(2) = 23 + a.22 + b.2 +6 =8+4a+2b+6 =14+ 4a+ 2b = 0

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b = - 7 -2a -(i)                                                                              

x3 + ax2 + bx +6 when divided by (x-3) leaves remainder 3.

p(3) = 3                                                                                      

p(3) = 33 + a.32 + b.3 +6= 27+9a +3b +6 =33+9a+3b = 3

11+3a +b =1 => 3a+b =-10 => b= -10-3a -(ii)                                    

Equating the value of b from (ii) and (i) , we have

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Substituting a = -3 in (i), we get

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Step-by-step explanation:

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Step-by-step explanation:

<u>Speed of Jaguar given:</u>

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<u>Solution:</u>

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