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Dominik [7]
3 years ago
9

*Please help, will reward*

Mathematics
1 answer:
hammer [34]3 years ago
8 0
After putting 20% down on her $140,000 house, Esmeralda will be borrowing $112,000. The price of 2 points on that loan amount is 2%×$112,000 = $2,240. If Esmeralda applies that amount to the down payment, her loan amount will be $109,760 and her payment will be ...
  A = P*(r/n)/(1 -(1 +r/n)^(-nt))
  A = 109,760*(.0575/12)/(1 -(1 +.0575/12)^-360)
  A = 640.53

Esmeralda's monthly payment will be about $641.
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What happens to 35 when you multiply it by 100
marusya05 [52]
You times it by one and then add the two zeros so your answer is 3,500
3 0
3 years ago
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10. The value of the 8th term is 78.
Yuri [45]

Answer: The answer is 88

Step-by-step explanation: It is recursive because you can add 78+10=88

5 0
3 years ago
6⁄10 _______ 9⁄12 A. > B. ≤ C. = D.
Ivanshal [37]
6/10 is equal to 0.60
9/12 is equal to 0.75
your answer is not above for D but if D is < then that would be the correct answer :)
7 0
3 years ago
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PLS HELP THIS IS HARD ANYONE PLS
Valentin [98]

This question is very oddly worded.  The domain is the set of x-values, but this is a set of (x,y) ordered pairs.

I'm reading this question as "Here's a function, { (1,5), (2,1), (-1,-7) }.  If this is reflected over the x-axis, what's the range?"

Assuming that is the question that is meant to be asked, reflecting a function over the x-axis will just change the signs of the y-values.

    (1,5) -> (1,–5)

    (2,1) -> (2,–1)

    (-1,-7) -> (-1,+7)

I'd pick the third option.

6 0
3 years ago
What are the two missing sides of the triangle ??
igor_vitrenko [27]
Remark
It's a right triangle so the Pythagorean Theorem applies. All you have to do is put the right things in the right places of the formula.

Givens
a = x
b = x + 4
c = 20

Formula and Substitution.
a^2 + b^2 = c^2
x^2 + (x + 4)^2 = 20^2

Solution
x^2 + x^2 + 8x + 16 = 20 Collect the like terms on the left.
2x^2 + 8x + 16 = 20  Subtract 20 from both sides.
2x^2 + 8x + 16 - 20 = 0  
2x^2 + 8x - 4 = 0         Divide through by 2
x^2 + 4x - 2 = 0

Use the quadratic formula
a = 1
b = 4
c = - 2

\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10; 
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} + 4(1)(2) } }{2} &#10;

From which x = (-4 +/- sqrt(24) ) / 2
x1 = (- 4 +/- sqrt(4*6) ) / 2
x1 = (- 4 +/- 2 sqrt(6) ) / 2
x1 = -2 + sqrt(6)
x2 = -2 - sqrt(6)  This is an extraneous root. No line can be minus.

x1 = + 0.4495
x2 = x + 4 = 4.4495
6 0
3 years ago
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