How many solutions does the system have? {2x+2y=8 {3x+y=8 2x+2y=8

Mathematics

2 answers:

umka2103 [35]3 years ago

4 0

Answer:

Step-by-step explanation:

first we put them in y = mx + b form...then we compare the slopes and the y int's. In y = mx + b form, the slope is in the m position and the y int is in the b position.

2x + 2y = 8

2y = -2x + 8

y = -x + 4......slope here is -1 and y int is 4

3x + y = 8

y = -3x + 8.....slope here is -3 and y int is 8

This system has 1 solution <===

================================

learn this...it helps

* if there are different slopes and different y int, then there is 1 solution

* if there are the same slopes and different y int, then there is no solutions because u have parallel lines

* if there are same slopes and same y int, there is infinite solutions because u have the same line

Vedmedyk [2.9K]3 years ago

4 0

Your solution is 1 learn this plz

You might be interested in

PLEASE help me with this question and I WILL love you forever But yeah please help me with the question.And EXPLAIN in words how

Rufina [12.5K]

Well on this problem recall area of a rectangle is defined by:

A = lw our w = 1/6 and our l = (x + $\frac{2}{3}$ ) we have let 'x' represent our original length.
$(x + \frac{2}{3} )( \frac{1}{6} )= \frac{11}{72}$
$\frac{1}{6} x+ \frac{2}{18} = \frac{11}{72}$
12x + 8 = 11
12x = 11 - 8
12x = 3
x = $\frac{3}{12} = \frac{1}{4}$ So our original length is $\frac{1}{4}$