Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
Answer:
a. yes, because there is a straight line that passes through the origin (0, 0). b. no, there is a straight line but it does not pass through the origin.
Step-by-step explanation:
Answer and Step-by-step explanation:
The answer is attached below
Answer:
2pi +6
Step-by-step explanation: First you can get the are of the triangle by doing (base *height)/2 this will be (3*4)/2 whcih is 6
Area of the half circle. To get the area of the circle u do radius^2*pi. this will be 2^2*pi in this example. so 4pi. because its half u have to to divide it by 2, so 4pi/2 is 2pi.
Now 2pi + 6 is the anwser
