8q+4=20
8q=16
q=2
hope this helps!
Answer:
Where:
And we can find the intercept using this:
On this case the correct answer would be:
E. none of the above
Since the intercept has no association between the increase/decrease of the dependent variable respect to the independent variable
Step-by-step explanation:
Assuming the following options:
A. there is a positive correlation between X and Y
B. there is a negative correlation between X and Y
C. if X is increased, Y must also increase
D. if Y is increased, X must also increase
E. none of the above
If we want a model 
where m represent the lope and b the intercept
Where:
And we can find the intercept using this:
On this case the correct answer would be:
E. none of the above
Since the intercept has no association between the increase/decrease of the dependent variable respect to the independent variable
Happy Pride Month!
Answer:
Option B
Step-by-step explanation:
Use Desmos graphing calculator for these probloms and type your qustion on the left box
<span>Simplifying
49x^2 + -9 = 0
Reorder the terms:
-9 + 49x^2 = 0
Solving
-9 + 49x^2 = 0
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '9' to each side of the equation.
-9 + 9 + 49x^2 = 0 + 9
Combine like terms: -9 + 9 = 0
0 + 49x^2 = 0 + 9
49x^2 = 0 + 9
Combine like terms: 0 + 9 = 9
49x^2 = 9
Divide each side by '49'.
x^2 = 0.1836734694
Simplifying
x^2 = 0.1836734694
Take the square root of each side:
x = {-0.428571429, 0.428571429}
hope this helps!!</span>
First let's reduce the feet to miles
there are 5280 feet in a mile therefore
26400 feet=5 miles
31680 feet=6 miles
Jet A(the first jet) descends 5 miles in 96 miles
Jet B(the second jet) descends 6 miles in 120 miles
We can compare these as fractions to see which is steeper. This can be viewed as slope and the origin (0,0) is the airport.
slope: 6/120=?=5/96
1/20=?=5/96
Now we know that 5/100 =1/20 so 5/96 must be bigger than 5/100 because you are dividing by a smaller number.
so 1/20<5/96
So Jet B is descending steeper than Jet A.
As for linear model, I don't exactly know what your teacher means but I think I actually used the linear model when I'm thinking of steepness as slope in the coordinate plane, I will include a picture.
In this extremely zoomed out graph, you can see the blue line is just slighly higher than the red line(slope as in explanation is way easier to tell) this could be seen as the linear model) :) Hope it helped!
