7y^4-19y^3-6y^2 factor the trinomial
1 answer:
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Answer:
could not be the same
Step-by-step explanation:
Given that approximately US drivers are agewise as follows:
<25 13.2
25-45 37.7%
>45 49.1%
Observations are made for a sample of 200 fatal accidents.
Let us create hypotheses as
(Two tailed chi square test at 5% significance level)
Age <25 25-45 >45
Expected 13.2 37.7 49.1 100
Observed 42 80 78 200
Expected no 26.4 75.4 98.2 200
Chi square 9.218181818 0.280636605 4.155193483 13.65401191
df = 2
p value = 0.001084
Since p <0.05 we reject null hypothesis
At the 0.05 level, the age distribution of drivers involved in fatal accidents within the state could not be the same as the age distribution of all US drivers as there seems to be significant difference.
Answer:
a. 5% of the employees will experience lost-time accidents in both years
b. 24% of the employees will suffer at least one lost-time accident over the two-year period
Step-by-step explanation:
a. What percentage of the employees will experience lost-time accidents in both years?
20% last year, of those who suffered last year, 25% during this year. So
5% of the employees will experience lost-time accidents in both years.
b. What percentage of the employees will suffer at least one lost-time accident over the two-year period?
5% during the two years.
10% during the current year. 25% of employees who had lost-time accidents last year will experience a lost-time accident during the current year.
So the 10% is composed of 5% during both years(25% of 20%) and 5% of the 80% who did not suffer during the first year.
First year yes, not on the second.
75% of 20%. So, total:
24% of the employees will suffer at least one lost-time accident over the two-year period