Answer:
Hans has done a mistake in the second step.
The correct answer is:
5x^2+13x-6=0
5x^2+15x-2x-6x=0 - 5. -6=-30 -30=15. -2
5x(1+3x)-2x(1+3x)=0
(5x-2x)(1+3x)=0
5-2x=0 1+3x=0
x=5/2 x=-1/3
Answers:
1. The n-intercept is 12. That means after 12 visits the amount of money on the gift car is $0.
2. The A(n)-intercept is 150. Before the visits, the amount of money on the gift car is $150.
Solution:
Amount of money on the gift card after n number of visits: A(n)=$150-$12.50 n
A(n)=150-12.50 n
1. n-intercept
A(n)=0→150-12.50 n =0
Solving for n: Subtracting 150 both sides of the equation:
150-12.50 n-150 = 0-150
-12.50 n = -150
Dividing both sides of the equation by -12.50:
(-12.50 n) / (-12.50) = (-150) / (-12.50)
n=12
The n-intercept is n=12; for n=12→A(12)=0. Point (n, A(n))=(12,0)
2. A(n) intercept
n=0→A(0)=150-12.50 (0)
A(0)=150-0
A(0)=150
The A(n) intercept is 150; for n=0→A(0)=150. Point (n, A(n))=(0,150)
Without any calculations it's evident it can't be neither B (both numbers are even, so they're divisible by 2) nor C (the numbers end in 0 and 5, so they're divisible by 5).
A.

Both numbers have a factor of 3, so they're not relatively prime.
That means it must be D. But, let's check it.

Indeed, those two numbers are relatively prime.
Answer:
y = 0.25x - 5
Step-by-step explanation:
Given line is 4x + y = 3
or y = -4x + 3
Comparing this with slope-intercept form y = mx + c :
slope of this line is -4
Product of slopes of perpendicular lines = -1
⇒ slope of a line perpendicular to this is
=
= 0.25
This line also passes through the point (-4,-6)
The equation of a line having slope m and passing through a point (h,k) is
y - k = m(x - h)
⇒ equation of line perpendicular to given line is y - (-6) = 0.25×{x - (-4)}
⇒ y + 6 = 0.25×(x + 4)
⇒ y + 6 = 0.25x + 1
⇒ <u>y = 0.25x - 5</u>
This is in the slope-intercept form y = mx + c with slope m = 0.25 and y-intercept (0,-5)