Which point could be removed in order to make the relation a function? {(0, 2), (3, 8), (–4, –2), (3, –6), (–1, 8), (8, 3)} Whic
myrzilka [38]
(3,-6) because you can't have two of the same x's in a function
Use the Pythagorean Theorem of a² + b² = c² to solve for x.
x² + (x + 3)² = (√117)²
x² + x² + 6x + 9 = 117
2x² + 6x + 9 = 117
2x² + 6x + 9 - 117 = 0
2x² + 6x - 108 = 0
2x² + 18x - 12x - 108 = 0
2x(x + 9) - 12(x + 9) = 0
(2x - 12)(x + 9) = 0
x = - 9, 6
Length cannot be negative so you can't use - 9.
x = 6. Option C is your answer.
Answer:
fx=
18/5(2.718282−0.1z)+6
mark him as brainlesit
Step-by-step explanation:
i think its right
B has two pre-images of -7 so it is not a function
Asa. the side is in the middle of the angles