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3 years ago

Why pH level test is important in lotion testing? Why it matter? Explain your answer

Chemistry

1 answer:

IceJOKER [234]3 years ago

3 0

Answer: The ph value of the skin plays an essential role in protecting the skin.

Explanation:

An acidic protective layer is crucial for the functioning of the skin's protective barrier. Neutralizes aggressive alkaline substances (eg, aggressive surfactants), inhibits bacterial growth and restores and maintains an optimal acidic environment in which natural flora can develop.

If there is a rise in the ph value of the skin, the nature of the skin may become disturbed. Essential epidermal lipids can no longer be synthesized, so in this case, the skin loses and dries. By breaking its protective function, the skin can become dry, sensitive, or extremely

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How many moles in 2.0g of carbon dioxide?

ANEK [815]

First you need to find out the Limiting reactant (LR). convert both reactants to the same thing. Check that the chemical equation is balanced. Now use stoichiometr and remember at moles, multiply: need moles, divide2 g / 42g/mol= 0.0477 mol propane mass propane/ Molar Mass propane = moles propane4 g / 32 g/mol= 0.125 mol oxygen X (1 mol/ 5 mol) = 0.025 mol propane oxygen is the LRmass O2 / MM O2 X (mol propane / mol O2)0.025 mol X (3 mol / 1 mol ) = .075 mol CO20.075 mol X (12 + 2*16) g /mol = 3.6 g CO2 In one step:2 g / 42g/mol X (3 mol / 1 mol ) X 48 g/mol = 6.86 g CO24 g / 32 g/mol X (3 mol / 5 mol ) X 48 g/mol = 3.6 g CO2mass/ MM X coefficient ratio X MM (new)

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3 years ago

Simple machines make work easier. Most simple machines reduce the amount of effort force needed to move an object. This cart has

Kruka [31]

I'm pretty sure it's D

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2 years ago

Which of the following metals will react with water to produce a metal hydroxide and hydrogen gas? a. Mg b. Li c. Al d. Pb

Stells [14]

I believe the answer is A) Mg.

5 0

2 years ago

Read 2 more answers

A mixture of methane and air is capable of being ignited only if the mole percent of methane is between 5% and 15%. A mixture co

DaniilM [7]

Answer:

Explanation:

The air 9% mole% methane have an average molecular weight of:

9%×16,04g/mol + 91%×29g/mol = 27,8g/mol

And a flow of 700000g/h÷27,8g/mol = 25180 mol/h

In the reactor where methane solution and air are mixed:

In = Out

Air balance:

91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)

Where X is the flow rate of air in mol/h = 20144 mol air/h

The air in the product gas is

95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = 289 kg O₂

43058 mol air×29g/mol 1249 kg air

Percent of oxygen is: $\frac{289kg}{1249 kg}$ =0,231 kg O₂/ kg air

I hope it helps!

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2 years ago

I have a few questions from my homework and I was wondering if I can get some help

sashaice [31]

Well it breaks down into small parts

3 0

2 years ago