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3 years ago

8

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri

um constant?

1 answer:

Nimfa-mama [501]3 years ago

8 0

Answer: The expression for equilibrium constant is $\frac{[NH_3]^2}{[H_2]^3[N_2]}$

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as $k_c$

For a general reaction:

$aA+bB\rightleftharpoons cC+dD$

The equilibrium constant is written as:

$k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

Chemical reaction for the formation of ammonia is:

$N_2+3H_3\rightleftharpoons 2NH_3$

$k_c=1.6\times 10^2$

Expression for $k_c$ is:

$k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

$1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}$

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Manganese metal can be obtained by the reaction of manganese dioxide with aluminium. 4Al(s) + 3MnOz(s) → 2 Al2O3(s) + 3 Mn(s) Ca

Snezhnost [94]

Answer : The enthalpy change of reaction is -1800 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given final reaction is,

$4Al(s)+3MnO_2(s)\rightarrow 2Al_2O_3(s)+3Mn(s)$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $2Al(s)+\frac{3}{2}O_2(g)\rightarrow Al_2O_3(s)$ $\Delta H_1=-1680kJ/mole$

(2) $Mn(s)+O_2(g)\rightarrow MnO_2(s)$ $\Delta H_2=-520kJ/mole$

First we will multiply reaction 1 by 2 and reverse reaction of reaction 2 by 3 then adding both the equation, we get :

The expression for final enthalpy is,

$\Delta H=[n\times \Delta H_1]+[n\times (-\Delta H_2)]$

where,

n = number of moles

$\Delta H=[2mole\times (-1680kJ/mole)]+[3\times -(-520kJ/mole)]$

$\Delta H=-1800kJ$

Therefore, the enthalpy change of reaction is -1800 kJ

8 0

3 years ago

A student is asked to standardize a solution of potassium hydroxide. He weighs out 1.08 g potassium hydrogen phthalate (KHC8H4O4

natka813 [3]

Answer:

A. 0.143 M

B. 0.0523 M

Explanation:

A.

Let's consider the neutralization reaction between potassium hydroxide and potassium hydrogen phthalate (KHP).

KOH + KHC₈H₄O₄ → H₂O + K₂C₈H₄O₄

The molar mass of KHP is 204.22 g/mol. The moles corresponding to 1.08 g are:

1.08 g × (1 mol/204.22 g) = 5.28 × 10⁻³ mol

The molar ratio of KOH to KHC₈H₄O₄ is 1:1. The reacting moles of KOH are 5.28 × 10⁻³ moles.

5.28 × 10⁻³ moles of KOH occupy a volume of 36.8 mL. The molarity of the KOH solution is:

M = 5.28 × 10⁻³ mol / 0.0368 L = 0.143 M

B.

Let's consider the neutralization of potassium hydroxide and perchloric acid.

KOH + HClO₄ → KClO₄ + H₂O

When the molar ratio of acid (A) to base (B) is 1:1, we can use the following expression.

$M_{A} \times V_{A} = M_{B} \times V_{B}\\M_{A} = \frac{M_{B} \times V_{B}}{V_{A}} \\M_{A} = \frac{0.143 M \times 10.1mL}{27.6mL}\\M_{A} =0.0523 M$

8 0

3 years ago

ANSWER FOR: How did the lab activities help you answer the lesson question "How do the processes of conduction, convection, and

Alenkinab [10]

<u>Answer</u>: Conduction, convection, and radiation move energy from the Sun to Earth and throughout Earth.

Without more information about the experiment itself, I would choose the above answer as correct. All the other statements are correct, however none of them relates to the earth distribution processes on Earth. The last statement does.

8 0

3 years ago

Read 2 more answers

What does an atom contain?

netineya [11]

Answer:

neutron, proton, and electrons

Explanation:

The protons and the neutrons make up the center of an atom which is called the nucleus

7 0

3 years ago

Lemon juice has a pH of about 2.0, compared with a pH of about 1.0 for stomach acid. Therefore, the concentration of H+ in stoma

LuckyWell [14K]

Answer:

The concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.

Explanation:

The H⁺ concentration of a solution is exponentially related to its pH value:

$\rm [H^{+}] = 10^{-pH}$ .

For lemon juice:

$\rm [H^{+}] = 10^{-2.0} = 0.01\; M$ .

For stomach acid:

$\rm [H^{+}] = 10^{-1.0} = 0.1\; M$ .

Thus, the concentration of H⁺ in stomach acid is approximately ten times greater than that of lemon juice.

5 0

3 years ago

Read 2 more answers