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Kazeer [188]
3 years ago
8

The equilibrium constant for the formation of ammonia from nitrogen and hydrogen is 1.6 × 102. what is the form of the equilibri

um constant?
Chemistry
1 answer:
Nimfa-mama [501]3 years ago
8 0

Answer: The expression for equilibrium constant is \frac{[NH_3]^2}{[H_2]^3[N_2]}

Explanation: Equilibrium constant is the expression which relates the concentration of products and reactants preset at equilibrium at constant temperature. It is represented as k_c

For a general reaction:

aA+bB\rightleftharpoons cC+dD

The equilibrium constant is written as:

k_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}

Chemical reaction for the formation of ammonia is:

N_2+3H_3\rightleftharpoons 2NH_3

k_c=1.6\times 10^2

Expression for k_c is:

k_c=\frac{[NH_3]^2}{[H_2]^3[N_2]}

1.6\times 10^2=\frac{[NH_3]^2}{[H_2]^3[N_2]}

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A substance that is ______ will NOT dissolve in a solvent. A) freezing B) insoluble C) evaporating D) soluble
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A certain compound was found to have the molecular formula C5H12O2. To which of the following compound classes could the compoun
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3 years ago
A sample of a pure element has a mass of 45.6g and contains 4.19 x 10 23 atoms. Identify the element.
max2010maxim [7]
<h2>Answer:</h2>

    ZINC

<h2>Explanation:</h2>

<em>To identify the element based on the informartion given, we have to find the molar mass since this mass is unique to each element.</em>

            Molar mass = mass ÷ moles

<em>We already know the mass based on the question, as such we now need to find the # of moles.</em>

           Since 1 mole contains 6.02214 × 10²³ atoms

      then let  x moles contain 4.19 × 10²³ atoms <em>(given in the question)</em>

<em>     </em><em> </em>   ⇒   x =  (4.19 × 10²³ atoms  ×  1 mol) ÷ 6.02214 × 10²³ atoms

              x  =  0.69577 mol

<em>Now that we have the moles we can substitute it into the molar mass equation and solve for the molar mass.</em>

           ⇒ molar mass = 45.6 g ÷ 0.69577 mol

           ⇒ molar mass ≈  65.54 g/mol

                    This molar mass is closest to that of ZINC.

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3 years ago
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