Question

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

Answer 1

Answer:

$m_{Ag}=135.8gAg$

$Y=88.4\%$

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

$m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg$

Next, given the actual yield of 120 g, we compute the percent yield via:

$Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%$

Regards!