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3 years ago

Cu + 2AgNO3 → Cu(NO3)2 + 2Ag

Chemistry

1 answer:

Eva8 [605]3 years ago

4 0

Answer:

$m_{Ag}=135.8gAg$

$Y=88.4\%$

Explanation:

Hello there!

In this case, according to the described chemical reaction, it is possible to compute the theoretical mass of silver as mass via the 1:2 mole ratio of copper to silver and their atomic mass in the periodic table, in order to perform the following stoichiometric setup:

$m_{Ag}=40.gCu*\frac{1molCu}{63.55gCu}*\frac{2molAg}{1molCu}*\frac{107.87gAg}{1molAg}\\\\ m_{Ag}=135.8gAg$

Next, given the actual yield of 120 g, we compute the percent yield via:

$Y=\frac{120g}{135.8g}*100\%\\\\Y=88.4\%$

Regards!

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In the background information, it was stated that CaF2 has solubility, at room temperature, of 0.00160 g per 100 g of water. How

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Answer:

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

Explanation:

First, by definition of solubility, in 100 g of water there are 0.0016 g of CaF₂. So, to know how many moles are 0.0016 g, you must know the molar mass of the compound. For that you know:

Ca: 40 g/mole
F: 19 g/mole

So the molar mass of CaF₂ is:

CaF₂= 40 g/mole + 2*19 g/mole= 78 g/mole

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 0.0016 grams of the compound how many moles are there?

$moles=\frac{0.0016 grams*1 mole}{78 grams}$

moles=2.05*10⁻⁵

2.05*10⁻⁵ moles of CF₂ can dissolve in 100 g of water.

Now, to answer the following question, you can apply the following rule of three: if by definition of density in 1 mL there is 1 g of CaF₂, in 1000 mL (where 1L = 1000mL) how much mass of the compound is there?

$mass of CaF_{2}=\frac{1000 mL*1g}{1mL}$

mass of CaF₂= 1000 g

Now you can apply the following rule of three: if there are 78 grams of CaF₂ in 1 mole, in 1000 grams of the compound how many moles are there?

$moles=\frac{1000 grams*1 mole}{78 grams}$

moles=12.82

12.82 moles of CaF₂ will dissolve in exactly 1.00 L of solution

5 0

3 years ago

How much heat will be given off when 1500 g of water cools down by 20 C? please help and explain:)))

docker41 [41]

Answer:

126000J

Explanation:

From the question given, we obtained the following information:

M = 1500g

C = 4.2J/g°C

ΔT = 20°C

Q =?

Q= MCΔT

Q = 1500 x 4.2 x 20 =

Q = 126000J

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3 years ago

How many liters of oxygen gas are there in 45.0g O, at 0 degrees C and 1 atm of pressure? make sure to round to the correct numb

ZanzabumX [31]

Answer:

You can use the pdf to help you

Explanation:

Download pdf

3 0

2 years ago

What is the energy of an electromagnetic wave with a frequency of 8•10^12 Hz?

aniked [119]

Hello!

Find the Energy of the Photon by Planck's Equation, given:

E (photon energy) =? (in Joule)

h (Planck's constant) = $6.626*10^{-34}\:J * s$

f (radiation frequency) = $8*10^{12}\:Hz$

Therefore, we have:

$E = h*f$

$E = 6.626*10^{-34}*8*10^{12}$

$E = 53.008*10^{-34+12}$

$E = 53.008*10^{-22}$

$\boxed{\boxed{E = 5.3008*10^{-21}\:Joule}}\end{array}}\qquad\checkmark$

I Hope this helps, greetings ... DexteR! =)

8 0

3 years ago

If the oxidation number of an atom decreases, the atom has undergone oxidation.

Bumek [7]

Oxidation is a process when an atom, a group of atoms, or an ion loses electrons.

For example,

Cu⁰ -------> Cu⁺² + 2e⁻. This is an oxidation process.

As we can see an oxidation number was 0, and it became +2. The oxidation number is increased. Oxidation number of the atom, when an atom has undergone oxidation, increases.

So, answer is b.False.

8 0

3 years ago