Answer:
The rate of disappearance of 
for this period is
Explanation:
Initial concentration of = x = 0.0138 M
Final concentration of = y = 0.00886 M
Time elapsed during change in concentration = Δt = 374 s
Change in concentration ,![\Delta [NO_2]](https://tex.z-dn.net/?f=%5CDelta%20%5BNO_2%5D)
= y - x = 0.00886 - 0.0138 M = -0.00494 M
The rate of disappearance of for this period is:
![\frac{\Delta [NO_2]}{\Delta t}=\frac{-0.00494 M}{374 s}=-1.32\times 10^{-5} M/s](https://tex.z-dn.net/?f=%5Cfrac%7B%5CDelta%20%5BNO_2%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B-0.00494%20M%7D%7B374%20s%7D%3D-1.32%5Ctimes%2010%5E%7B-5%7D%20M%2Fs)
Answer:
See explanation
Explanation:
Now the element sodium has electronic configuration of [Ne]3s1
Florine has an electronic configuration of [He] 2p5
We know that in the formation of sodium flouride, sodium looses one electron to form Na^+ while F gains one electron to form F^-. So the electronic configuration of both Na^+ and F^- now become; 1s2 2s2 2p6
Answer:
c i believe
Explanation:
Good luck and sorry if im wrong
